How to open a directory and print out dates of all the files?

[new bie]

Need to write a perl script to open a dir and print out the date of all files last modified. This is what I have but keep getting error...

use File::stat;
open "D,"$ARGV[0]") or die "Can't open dir\n";

while(defined($file = readdir D))
{
next if ! -T $file;
$last_mod = (stat($file))[9] or die "Can't stat\n";
print"$file:\t$last_mod\n";
}

Keep getting "Can't stat"!!! What did I do wrong??? Any help is appreciated....

[Oralloy]

new bie,

If you read the File::stat module documentation, you'll see that there are problems with the -T operator. I don't know if this is what is affecting you or not.

Are you, perhaps, running on a Windows box, rather than a Linux box?

[Oralloy]

Curse, what am I saying. Even if -T fails, you're still failing to stat(), aren't you?

Can you add the file name that's causing problems?

use File::stat;
open "D,"$ARGV[0]") or die "Can't open dir\n";
 
while(defined($file = readdir D))
{
  next if ! -T $file;
  $last_mod = (stat($file))[9] or die "Can't stat '$file'\n";
  print"$file:\t$last_mod\n";
}

BTW, here is the man page from perl.org.

[RonB]

The open function is used to open a file, not a directory. You need to use opendir.

perldoc -f open
http://perldoc.perl.org/functions/open.html

perldoc -f opendir
http://perldoc.perl.org/functions/opendir.html

[Oralloy]

@RonB - good catch, man! I think you just solved all his problems.