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Replacing value of a string and adding original value to an array?

P: 1
Okay, so I want to create a loop that continuously asks for a set of three numbers, squares them, adds them together, then compares them. I'm not really done, so I apologize if you don't really get what I'm trying to do here.

Here's what I've got so far:

use warnings;

print "Enter the first number: ";
$number1 = <STDIN>;
print "Enter the second number: ";
$number2 = <STDIN>;
print "Enter the third number: ";
$number3 = <STDIN>;

$total = $number3**2+$number2**2+$number1**2;
print "$total\n";

print "Are you done? Enter 1 for yes or 2 for no.\n";
$answer4 = <STDIN>;

if($answer4==1) {
elsif ($answer4==2) {

## here I wanna compare the numbers
print "You have finished.";

I'm only a beginner at this, so I apologize if it's kinda simple.
But I want the scalar variable $total to be continuously re-evaluated for each time it loops, but add its original value to an array.

I don't really know if that's possible, but if it is, please help.
Jul 30 '10 #1
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2 Replies

P: 70
What do you mean when you say "then compares them"? Compare what to what?

It is a good idea to chomp your input.
Jul 31 '10 #2

Expert 100+
P: 410
I am not sure what you want "to compare" here. But if you want to create the scalar fresh with each iteration, use 'my' (for local scope). You can later push each value into an array.

Expand|Select|Wrap|Line Numbers
  1. my $total = $number3**2+$number2**2+$number1**2;
  2. print "$total\n";
  4. push @totals,$total;
Aug 3 '10 #3

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