comparision of 32 bit signed numbers

raghavendrap

Hello friends,
I need help in comparision of 32 bit signed numbers.
I am generating random signed numbers using some logic & when i am doing addition of two numbers i am getting maximum value 0X80000000.
how to avoid this?
Example:#
In the above example, $result will overflow i.e exceeds the range 0x8000000 after addition of two signed numbers, & am getting result as 0x8000000 only, in order to avoid this what i need to do?


Thanks
Raghavendra

Oct 31 '08 #1

crazy4perl

Hello friends,
I need help in comparision of 32 bit signed numbers.
I am generating random signed numbers using some logic & when i am doing addition of two numbers i am getting maximum value 0X80000000.
how to avoid this?
Example:#

Expand|Select|Wrap|Line Numbers

1. use strict ;
2.  
3. my $a;
4. my $b;
5. my $result;
6.  
7. $range = 2**31; # 2^(n-1): n=32
8.  $min = -2**31; #lowest integer
9.  $val= int(rand($range)) + $min;
10.  print "$val\n"
11.  
12.   $a = $val;
13.   $b = $val;
14.   $result = $a+$b;
15.  

In the above example, $result will overflow i.e exceeds the range 0x8000000 after addition of two signed numbers, & am getting result as 0x8000000 only, in order to avoid this what i need to do?


Thanks
Raghavendra

I dont know but its working fine for me

val := -1149894656
result := -2299789312

Oct 31 '08 #2

raghavendrap

hey man i have just posted an example in order understand my question,
if overflows what to do ? & if it in hexadecimal format how to compare with >0 or <0, i am getting the wrong result

Oct 31 '08 #3