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how to increment character value

Sorry guys just wanted to learn. I have a database. When I do the search using mysql suppose i have 100 records I wanted to keep the first second ... in the loop to be retrain.
like an integer you may use $count = $count + 1;
then in the second round count value would be 2.
In this case I wanted the character to retain the old value incrementally
ex. first loop. kind = a
second. kind = a , b
3rd. kind = a , b c and so on

thanks. I need your help. thanks a lot
Dec 17 '06 #1
3 8920
GunnarH
83
I for one don't understand what you are talking about. Maybe it is because English isn't my first lanuage...

You may want to try talking Perl instead of English, i.e. show us the code you have prepared in an attempt to do whatever you are trying to do.
Dec 17 '06 #2
I for one don't understand what you are talking about. Maybe it is because English isn't my first lanuage...

You may want to try talking Perl instead of English, i.e. show us the code you have prepared in an attempt to do whatever you are trying to do.
-

$dbh = DBI->connect('dbi:mysql:dbname,user, pass);
#prepare and execute SQL statement
$sqlstatement="SELECT reg_id, category_id, category_name FROM table1 where category_id = \'$category_id\' ";
$sth = $dbh->prepare($sqlstatement);
$sth->execute ||
die "Could not execute SQL statement ... maybe invalid?";

print "<table border = 0>";
print "<td><p align=\"center\"><b>Reg ID</b></td>";
print "<td><p align=\"center\"><b>Category ID</b></td>";
print "<td><p align=\"center\"><b>Category Name</b></td>";
print "<tr>";
#output database results
while (@row=$sth->fetchrow_array)
{

my $query = "UPDATE table2 set category_name = \"$row[2]\" where reg_id = \"$row[0]\" ";



}

table1 having 100 records
the category_name under table2 are empty I wanted to fill this empty column with the value table1 under category_name would be placed using the condition of reg_id both table have same common entry.

Thanks
Dec 17 '06 #3
Do you mean something like this???

Expand|Select|Wrap|Line Numbers
  1. for ( $i=26, $c='a' ; $i ; $i--, $c=chr(ord($c)+1) ) { printf("$c\n"); }
Greetz, Doc
Dec 19 '06 #4

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