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variation on (?) call subroutine by reference

I know that if $subname contains the name of the subroutine I want to call,
I can call that subroutine via

However, my subroutine names are in an array, so if I want to call
$subname[3] I've tried

But, that doesn't work, and I'm not having much luck finding such an
example. If I'm doing something truly numbskulled, I do apologize!

I do realize I could go this route:
$this_sub = $subname[3];

That just seems so clunky and unnecessary, no?

Jul 19 '05 #1
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