I have created a calculation in a Discoverer worksheet and am trying to produce a subtotal of the results-however, Discoverer keeps on failing . As I am new to the system is there something additional that I should be doing in order to create this total?
Thanks
11 4165
What I assume from yur POST is that U r not able to compute SUB-Results from the TOTAL:
In that case why dont you try computing the SUB-TOTALS in the Work sheet itself (using GROUP BY clause in the Query) and then use that column in your Work Book.
Thanks for your reply but as I'm so new to the system,I'm not sure what you mean.
The calcultions That I'm using are:
Calculation4:
CASE WHEN Positions.Actual Headcount = 0 then 1 ELSE Positions.Actual Headcount END
This is to avoid a divide by zero in the following:
Calculation7:
Organisation Profile.Postion Fte/Calculation4
When then try to produce a subtotal on Calculation7, the worksheet fails.
Is there a way around this.?
Thanks.
Thanks for your reply but as I'm so new to the system,I'm not sure what you mean.
The calcultions That I'm using are:
Calculation4:
CASE WHEN Positions.Actual Headcount = 0 then 1 ELSE Positions.Actual Headcount END
This is to avoid a divide by zero in the following:
Calculation7:
Organisation Profile.Postion Fte/Calculation4
When then try to produce a subtotal on Calculation7, the worksheet fails.
Is there a way around this.?
Thanks.
Check for calculation examples here
Thanks for your reply but as I'm so new to the system,I'm not sure what you mean.
The calcultions That I'm using are:
Calculation4:
CASE WHEN Positions.Actual Headcount = 0 then 1 ELSE Positions.Actual Headcount END
This is to avoid a divide by zero in the following:
Calculation7:
Organisation Profile.Postion Fte/Calculation4
When then try to produce a subtotal on Calculation7, the worksheet fails.
Is there a way around this.?
Thanks.
Please post the error that the worksheet displays?
Please post the error that the worksheet displays?
Why dont you combine the two calculations in to one and just use one calculation:
Something Like:
CASE WHEN <col_nam> > 0 THEN <colnam> /<col_nam> ELSE <colnam>/1 END
The error message that I get whenever I try to total Calculation7is:
"No data is shown because an error occurred while running the query"
-not very informative I'm afraid.
Thanks for the advice about combining the calculations-I'll have a go.
Cheers
The error message that I get whenever I try to total Calculation7is:
"No data is shown because an error occurred while running the query"
-not very informative I'm afraid.
Thanks for the advice about combining the calculations-I'll have a go.
Cheers
Do POST back after testing for single calculation.
The calculation worked fine but the worksheet failed when I introduced a sum operation on the calculation.
Thanks
The calculation worked fine but the worksheet failed when I introduced a sum operation on the calculation.
Thanks
U are trying to create one more calculation that calculates SUM (previous calculation) ??
Pleas POST yur CALCULATION CODE for my reference
Hi,
Thanks for spending your time over this. I created the following as a calculation
(Calculation7). I then used Calculation7 in a SUM calculation. By itself, Calculation7 worked fine but when quoted in a SUM calculation the Worksheet failed.
CASE WHEN Positions.Actual Headcount > 0 THEN Organisation Profile.Positions Fte/Positions. Actual Headcount ELSE Organisation Profile.Positions Fte/1 END
Regards
Graham
Hi,
Thanks for spending your time over this. I created the following as a calculation
(Calculation7). I then used Calculation7 in a SUM calculation. By itself, Calculation7 worked fine but when quoted in a SUM calculation the Worksheet failed.
CASE WHEN Positions.Actual Headcount > 0 THEN Organisation Profile.Positions Fte/Positions. Actual Headcount ELSE Organisation Profile.Positions Fte/1 END
Regards
Graham
I think you cannot use one calculation in to another as you had the same problem before also. That is why i asked you to combine the two in to one.
Now why dont you try computing the SUM in the same calculation itself.
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