XPath expression

[piramido]

Hello,

I'm in trouble with a simple XPath expression. I've got the following
XML file

<?xml version="1.0" encoding="UTF-8"?>
<a>
<b>
<c>A</c>
</b>
<b>
<c>B</c>
</b>
<b>
<c>C</c>
</b>
<b>
<c>D</c>
<c>E</c>
<c>F</c>
<c>G</c>
</b>
</a>

and I'd like to reference the c-element with content B, i.e. the
second c-element in the file. But when I execute a/b/c[2], I get the c-
element with content E (the fifth one). Can somebody give me a hint in
what is wrong with this expression. In my opinion, at first a/b/c is
evaluated, which give a set of 7 nodes (7 c-element). Out of this set
the second node is taken, which would be the c-element with content B.

Best regards,
Sascha

[Richard Tobin]

In article <11*********************@o80g2000hse.googlegroups. com>,
piramido <pi******@googlemail.comwrote:

>and I'd like to reference the c-element with content B, i.e. the
second c-element in the file. But when I execute a/b/c[2], I get the c-
element with content E (the fifth one). Can somebody give me a hint in
what is wrong with this expression. In my opinion, at first a/b/c is
evaluated, which give a set of 7 nodes (7 c-element). Out of this set
the second node is taken, which would be the c-element with content B.

That's not how it works. You don't get the second node of a/b/c;
you get the c[2] of a/b. Only the fourth a/b has a c[2], and that's
the one you get.

(a/b/c)[2] will select the right element.

-- Richard
--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

[Philippe Poulard]

Richard Tobin a écrit :

In article <11*********************@o80g2000hse.googlegroups. com>,
piramido <pi******@googlemail.comwrote:

>and I'd like to reference the c-element with content B, i.e. the
second c-element in the file. But when I execute a/b/c[2], I get the c-
element with content E (the fifth one). Can somebody give me a hint in
what is wrong with this expression. In my opinion, at first a/b/c is
evaluated, which give a set of 7 nodes (7 c-element). Out of this set
the second node is taken, which would be the c-element with content B.

That's not how it works. You don't get the second node of a/b/c;
you get the c[2] of a/b. Only the fourth a/b has a c[2], and that's
the one you get.

and a/b/c[1] will give you the 4 c elements that contain A B C D : you
evaluate a step upon the result of the previous one ; but as Richard
shows you, () are used for grouping

>
(a/b/c)[2] will select the right element.

-- Richard

--
Cordialement,

///
(. .)
--------ooO--(_)--Ooo--------
| Philippe Poulard |
-----------------------------
http://reflex.gforge.inria.fr/
Have the RefleX !

[jasonturner76]

Have a look at Xml Studio, it has a free XPath visualiser.

http://www.liquid-technologies.com/P...nShots.aspx?11
On 29 Oct, 02:01, piramido <[e-mail]:

Hello,

I'm in trouble with a simple XPath expression. I've got the following
XML file

<?xml version="1.0" encoding="UTF-8"?>
<a>
<b>
<c>A</c>
</b>
<b>
<c>B</c>
</b>
<b>
<c>C</c>
</b>
<b>
<c>D</c>
<c>E</c>
<c>F</c>
<c>G</c>
</b>
</a>

and I'd like to reference the c-element with content B, i.e. the
second c-element in the file. But when I execute a/b/c[2], I get the c-
element with content E (the fifth one). Can somebody give me a hint in
what is wrong with this expression. In my opinion, at first a/b/c is
evaluated, which give a set of 7 nodes (7 c-element). Out of this set
the second node is taken, which would be the c-element with content B.

Best regards,
Sascha

[piramido]

Hello Richard,

it works. Thank you so much!

Kind regards,
Sascha