XSLT: select n-th element (how to use position?)

[Gerald Aichholzer]

Hello NG,

I have an XML document looking similiar to:

<document>
<section>
<group>
<symbol>...</symbol> <!-- n=1 -->
<symbol>...</symbol> <!-- n=2 -->
...
<symbol>...</symbol> <!-- n=x -->
</group>
<symbol>...</symbol> <!-- n=x+1 -->
<symbol>...</symbol> <!-- n=x+2 -->
...
<group>
</group>
...
</section>
<section>
</section>
...
</document>
I need to select the n-th symbol (and all subnodes),
where n is the symbol number in the whole document.

Is this possible? If it is how will I be able to
achieve this?

AFAIK position() starts counting with 1 for each
parent element - isn't it?

thanx in advance,
Gerald

[Martin Honnen]

Gerald Aichholzer wrote:

I have an XML document looking similiar to:

<document>
<section>
<group>
<symbol>...</symbol> <!-- n=1 -->
<symbol>...</symbol> <!-- n=2 -->
...
<symbol>...</symbol> <!-- n=x -->
</group>
<symbol>...</symbol> <!-- n=x+1 -->
<symbol>...</symbol> <!-- n=x+2 -->
...
<group>
</group>
...
</section>
<section>
</section>
...
</document>
I need to select the n-th symbol (and all subnodes),
where n is the symbol number in the whole document.

You can always do
(//symbol)[last()]
to access the last of all <symbol> elements at all levels.
Perhaps
(/document/section//symbol)[last()]
is all you need with that XML.
--

Martin Honnen
http://JavaScript.FAQTs.com/

[Gerald Aichholzer]

Martin Honnen wrote:

Gerald Aichholzer wrote:

I have an XML document looking similiar to:

<document>
<section>
<group>
<symbol>...</symbol> <!-- n=1 -->
<symbol>...</symbol> <!-- n=2 -->
...
<symbol>...</symbol> <!-- n=x -->
</group>
<symbol>...</symbol> <!-- n=x+1 -->
<symbol>...</symbol> <!-- n=x+2 -->
...
<group>
</group>
...
</section>
<section>
</section>
...
</document>
I need to select the n-th symbol (and all subnodes),
where n is the symbol number in the whole document.

You can always do
(//symbol)[last()]
to access the last of all <symbol> elements at all levels.
Perhaps
(/document/section//symbol)[last()]
is all you need with that XML.

Thank you for your information. n is specifid in a
parameter. Now I'm using the following wich works:

(/document//symbol)[position()=$symbolpos]
Gerald