A better xPath statement

[mTbrains]

I'm trying to pull out just three elements with a particular content
from a list of elements
my xml:

<content>
<topic>
<name>Sport</name>
....
</topic>
...
<topic>
<name>Health</name>
...
</topic>
.....
</content>
Here's what works in my xsl file, but there's probably a
better/easier/more efficient way of doing it:

<xsl:for-each select="topic[./name='Sports']| topic[./name='Movies']|
topic[./name='US News']">

Thanks in advance...martin

[David Carlisle]

"mTbrains" <ma*************@gmail.com> writes:

I'm trying to pull out just three elements with a particular content
from a list of elements
my xml:

<content>
<topic>
<name>Sport</name>
....
</topic>
...
<topic>
<name>Health</name>
...
</topic>
....
</content>
Here's what works in my xsl file, but there's probably a
better/easier/more efficient way of doing it:

<xsl:for-each select="topic[./name='Sports']| topic[./name='Movies']|
topic[./name='US News']">

Thanks in advance...martin

well you could (always) drop the ./ as the Xpath is the same without
that.

then something like

<xsl:for-each select="topic[name='Sports' or name='Movies' or name='US
News']

or a bit shorter but perhaps a little less clear:

<xsl:for-each select="topic[name[.='Sports' or .='Movies' or .='US News']]

In XPath2 you will be able to do

<xsl:for-each select="topic[name=('Sports','Movies','US News')]

David

[Martin Honnen]

mTbrains wrote:

I'm trying to pull out just three elements with a particular content
from a list of elements
my xml:

<content>
<topic>
<name>Sport</name>
....
</topic>
...
<topic>
<name>Health</name>
...
</topic>
....
</content>
Here's what works in my xsl file, but there's probably a
better/easier/more efficient way of doing it:

<xsl:for-each select="topic[./name='Sports']| topic[./name='Movies']|
topic[./name='US News']">

topic[name = 'Sports' or name = 'Movies' or name = 'US News']

--

Martin Honnen
http://JavaScript.FAQTs.com/