XSLT: How to find a node containing TWO matching children?

[bearclaws]

I have the following XML:

<AAA>
<BBB>
<CCC>111</CCC>
<CCC>222</CCC>
</BBB>
<BBB>
<CCC>333</CCC>
<CCC>444</CCC>
</BBB>
</AAA>

....and want to loop through AAA to find all BBBs that contain CCC nodes
matching 333 AND 444.

Any thoughts on the most effecient syntax for this?

Thanks,
BC

[Joris Gillis]

Tempore 18:40:18, die Thursday 10 March 2005 AD, hinc in foro {comp.text.xml} scripsit bearclaws <go**********@bencannon.com>:

...and want to loop through AAA to find all BBBs that contain CCC nodes
matching 333 AND 444.

what about "AAA/BBB[CCC='333' and CCC='444']" ?
regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-v...i?userid=38041)
"Quot capita, tot sententiae" - Terentius , Phormio 454

[Martin Honnen]

bearclaws wrote:

I have the following XML:

<AAA>
<BBB>
<CCC>111</CCC>
<CCC>222</CCC>
</BBB>
<BBB>
<CCC>333</CCC>
<CCC>444</CCC>
</BBB>
</AAA>

...and want to loop through AAA to find all BBBs that contain CCC nodes
matching 333 AND 444.

If <AAA> is the root element there is not much to loop through, as for
an XPath you would need
/AAA/BBB[CCC = '333' and CCC = '444']

--

Martin Honnen
http://JavaScript.FAQTs.com/

[bearclaws]

thanks! I was making my statement *much* more complicated than it
needed to be!

BC