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Quick XSLT Question

Does the following code have any defined behavior in XSLT or XPath? I have
tried this before and it didn't do what I thought it should do. Instead, I
had to use the local-name() function and compare it with a string
representing the element of interest.

<xsl:if test=". = SomeElement">
</xsl:if>
Jul 20 '05 #1
2 1164
"Mike King" <em*****@excite.com> writes:
Does the following code have any defined behavior in XSLT or XPath? I have
tried this before and it didn't do what I thought it should do. Instead, I
had to use the local-name() function and compare it with a string
representing the element of interest.

<xsl:if test=". = SomeElement">
</xsl:if>

it tests if the string value of the current node is equal to the string
value of its SomeElement child so if the current element is x it would
be true on

<x><a/><b/><SomeElement>aaa</SomeElement></x>

as they both have string value aaa.

You probably wanted

test="self::SomeElement"

which tests if the current node is a SomeElement element.

david
Jul 20 '05 #2
> it tests if the string value of the current node is equal to the string
value of its SomeElement child so if the current element is x it would
be true on

<x><a/><b/><SomeElement>aaa</SomeElement></x>

as they both have string value aaa.

You probably wanted

test="self::SomeElement"

which tests if the current node is a SomeElement element.

david

Thank you very much!
Jul 20 '05 #3

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