xsl:sort

Example XML:
<?xml version="1.0" encoding="UTF-8" ?>
<root>
<foo>
<index>1></index>
<bar>
<child />
<child />
</bar>
</foo>
<foo>
<index>n</index>
<bar>
<child />
<child />
</bar>
</foo>
</root>

My question is (as I understand pieces of how xsl:apply-templates works with
xsl:sort) why does this work:
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>

<xsl:template match="root">
<xsl:apply-templates>
<xsl:sort select="index" order="descending" />
</xsl:apply-templates>
</xsl:template>

Since I haven't (at least without assuming) that I'm sorting 'foo' elements.

Thanks for any input.

[Dimitre Novatchev]

Why do you think this shouldn't work?
=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

<sm****@bluehome.com> wrote in message news:niZtb.62808$jy.24811@clgrps13...

Example XML:
<?xml version="1.0" encoding="UTF-8" ?>
<root>
<foo>
<index>1></index>
<bar>
<child />
<child />
</bar>
</foo>
<foo>
<index>n</index>
<bar>
<child />
<child />
</bar>
</foo>
</root>

My question is (as I understand pieces of how xsl:apply-templates works with xsl:sort) why does this work:
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>

<xsl:template match="root">
<xsl:apply-templates>
<xsl:sort select="index" order="descending" />
</xsl:apply-templates>
</xsl:template>

Since I haven't (at least without assuming) that I'm sorting 'foo' elements.
Thanks for any input.