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New to XML. Need help reading XML.

P: n/a
Here's my XML:

<?xml version="1.0" ?>
<AppMode Type="Network">
<CurrentFolder Path="c:\tabs">
<Tabs>
<FilePath>tabs\Justin.tab</FilePath>
<FilePath>tabs\Julie.tab</FilePath>
*****There could be 1 of these or 100....quantity can change*****
</Tabs>
</CurrentFolder>
</AppMode>
All I need to do is load "Network" and "c:\tabs" into variables. Then each
FilePath goes into an array.

The following code gives me everything but Julie.tab. It only gives me one
of the FilePaths. I'm not even sure if this is the right/best way to do
this:

Dim XMLReader As XmlTextReader = New XmlTextReader("")
XMLReader.WhitespaceHandling = WhitespaceHandling.None

XMLReader.Read()
XMLReader.Read()
MsgBox(XMLReader.GetAttribute("Type"))

XMLReader.Read()
MsgBox(XMLReader.GetAttribute("Path"))

XMLReader.Read()

While Not XMLReader.EOF *****Why isn't this looping?

XMLReader.Read()

If Not XMLReader.IsStartElement() Then
Exit While
End If

MsgBox(XMLReader.ReadElementString("FilePath"))

End While

XMLReader.Close()

Any help would be greatly appreciated!

Jul 26 '08 #1
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5 Replies


P: n/a
Justin wrote:
Here's my XML:

<?xml version="1.0" ?>
<AppMode Type="Network">
<CurrentFolder Path="c:\tabs">
<Tabs>
<FilePath>tabs\Justin.tab</FilePath>
<FilePath>tabs\Julie.tab</FilePath>
*****There could be 1 of these or 100....quantity can change*****
</Tabs>
</CurrentFolder>
</AppMode>
All I need to do is load "Network" and "c:\tabs" into variables. Then
each FilePath goes into an array.
One way is to use XPath to find the nodes:

Dim doc As New XPathDocument("..\..\XMLFile1.xml")
Dim nav As XPathNavigator =
doc.CreateNavigator().SelectSingleNode("AppMode")
Dim type As String = nav.GetAttribute("Type", "")
Console.WriteLine("Type: {0}", type)
nav = nav.SelectSingleNode("CurrentFolder")
Dim path As String = nav.GetAttribute("Path", "")
Console.WriteLine("Path: {0}", path)
Dim filePaths As XPathNodeIterator = nav.Select("Tabs/FilePath")
Console.WriteLine("Found {0} file path(s):", filePaths.Count)
Dim paths(filePaths.Count) As String
Dim i As Integer = 0
For Each filePath As XPathNavigator In filePaths
paths(i) = filePath.Value
Console.WriteLine(paths(i))
i = i + 1
Next
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/
Jul 26 '08 #2

P: n/a
Hi Justin,

From your description, you want to extract some certain values from an XML
document. In .net framework, there is quite rich API support for XML query
and processing. Here you have three different possible means to do it:

1. Use the xmlreader as you've tried, this is a memory efficient approahc,
but maybe more difficult to code(when xml is complex)

2. use XmlDocument + Xpath query, this is quite simple code

3. If you can use .NET 3.5, then "Linq to XML" is quite a good weapon you
can utilize

Here I've produced sample code (extracting the elements you want) for all
of the 3 approaches mentioned above:

===========using XML Reader================
private void btnReader_Click(object sender, EventArgs e)
{
StreamReader sr = new StreamReader(@"..\..\test.xml",
Encoding.UTF8);
XmlReader xr = XmlReader.Create(sr);

List<stringpaths = new List<string>();

while (xr.Read())
{
if (xr.IsStartElement("AppMode"))
{
MessageBox.Show(xr.GetAttribute("Type"));
}else if(xr.IsStartElement("CurrentFolder"))
{
MessageBox.Show(xr.GetAttribute("Path"));
}
else if (xr.IsStartElement("FilePath"))
{
paths.Add(xr.GetAttribute("Path"));
}
}

MessageBox.Show("paths count: " + paths.Count);
sr.Close();
}
=====================

========USE XML document + xpath query==============
private void btnXmlDoc_Click(object sender, EventArgs e)
{
XmlDocument doc = new XmlDocument();
doc.Load(@"..\..\test.xml");

string type =
doc.SelectSingleNode("/AppMode").Attributes["Type"].Value;
string curfolder =
doc.SelectSingleNode("/AppMode/CurrentFolder").Attributes["Path"].Value;

XmlNodeList files = doc.SelectNodes("//FilePath");

List<stringpaths = new List<string>();

foreach (XmlNode pnode in files)
{
paths.Add(pnode.InnerText);
}

MessageBox.Show("type: " + type + "\r\n"
+ "current folder: " + curfolder + "\r\n"
+ "paths count: " + paths.Count);
}
==============================

============ use LINQ TO XML ===================
private void btnLinq_Click(object sender, EventArgs e)
{
StreamReader sr = new StreamReader(@"..\..\test.xml",
Encoding.UTF8);
XDocument xdoc = XDocument.Load(sr);
sr.Close();
string type = xdoc.Element("AppMode").Attribute("Type").Value;
var cfs = from cf in xdoc.Descendants("CurrentFolder")
select cf.Attribute("Path").Value;

string curfolder = cfs.First();

var paths = from fp in xdoc.Descendants("FilePath")
select fp.Value;

List<stringfpaths = paths.ToList();

MessageBox.Show("type: " + type + "\r\n"
+ "current folder: " + curfolder + "\r\n"
+ "paths count: " + fpaths.Count);

}
=============================

if you want to know more about LINQ to XML, please have a look at the MSDN
reference:

#.NET Language-Integrated Query for XML Data
http://msdn.microsoft.com/en-us/library/bb308960.aspx

Sincerely,

Steven Cheng

Microsoft MSDN Online Support Lead
Delighting our customers is our #1 priority. We welcome your comments and
suggestions about how we can improve the support we provide to you. Please
feel free to let my manager know what you think of the level of service
provided. You can send feedback directly to my manager at:
ms****@microsoft.com.

==================================================
Get notification to my posts through email? Please refer to
http://msdn.microsoft.com/subscripti...ult.aspx#notif
ications.

Note: The MSDN Managed Newsgroup support offering is for non-urgent issues
where an initial response from the community or a Microsoft Support
Engineer within 1 business day is acceptable. Please note that each follow
up response may take approximately 2 business days as the support
professional working with you may need further investigation to reach the
most efficient resolution. The offering is not appropriate for situations
that require urgent, real-time or phone-based interactions or complex
project analysis and dump analysis issues. Issues of this nature are best
handled working with a dedicated Microsoft Support Engineer by contacting
Microsoft Customer Support Services (CSS) at
http://msdn.microsoft.com/subscripti...t/default.aspx.
==================================================
This posting is provided "AS IS" with no warranties, and confers no rights.
--------------------
>From: "Justin" <No**@None.com>
Subject: New to XML. Need help reading XML.
Date: Sat, 26 Jul 2008 00:24:30 -0700
>
Here's my XML:

<?xml version="1.0" ?>
<AppMode Type="Network">
<CurrentFolder Path="c:\tabs">
<Tabs>
<FilePath>tabs\Justin.tab</FilePath>
<FilePath>tabs\Julie.tab</FilePath>
*****There could be 1 of these or 100....quantity can change*****
</Tabs>
</CurrentFolder>
</AppMode>
All I need to do is load "Network" and "c:\tabs" into variables. Then
each
>FilePath goes into an array.

The following code gives me everything but Julie.tab. It only gives me
one
>of the FilePaths. I'm not even sure if this is the right/best way to do
this:

Dim XMLReader As XmlTextReader = New XmlTextReader("")
XMLReader.WhitespaceHandling = WhitespaceHandling.None

XMLReader.Read()
XMLReader.Read()
MsgBox(XMLReader.GetAttribute("Type"))

XMLReader.Read()
MsgBox(XMLReader.GetAttribute("Path"))

XMLReader.Read()

While Not XMLReader.EOF *****Why isn't this looping?

XMLReader.Read()

If Not XMLReader.IsStartElement() Then
Exit While
End If

MsgBox(XMLReader.ReadElementString("FilePath"))

End While

XMLReader.Close()

Any help would be greatly appreciated!

Jul 28 '08 #3

P: n/a
Perfect! Thanks for the info. After reading about 20 pages including MS I
couldn't figure out how to loop at the end.

This worked like a charm!
"Martin Honnen" <ma*******@yahoo.dewrote in message
news:eg**************@TK2MSFTNGP04.phx.gbl...
Justin wrote:
>Here's my XML:

<?xml version="1.0" ?>
<AppMode Type="Network">
<CurrentFolder Path="c:\tabs">
<Tabs>
<FilePath>tabs\Justin.tab</FilePath>
<FilePath>tabs\Julie.tab</FilePath>
*****There could be 1 of these or 100....quantity can change*****
</Tabs>
</CurrentFolder>
</AppMode>
All I need to do is load "Network" and "c:\tabs" into variables. Then
each FilePath goes into an array.

One way is to use XPath to find the nodes:

Dim doc As New XPathDocument("..\..\XMLFile1.xml")
Dim nav As XPathNavigator =
doc.CreateNavigator().SelectSingleNode("AppMode")
Dim type As String = nav.GetAttribute("Type", "")
Console.WriteLine("Type: {0}", type)
nav = nav.SelectSingleNode("CurrentFolder")
Dim path As String = nav.GetAttribute("Path", "")
Console.WriteLine("Path: {0}", path)
Dim filePaths As XPathNodeIterator = nav.Select("Tabs/FilePath")
Console.WriteLine("Found {0} file path(s):", filePaths.Count)
Dim paths(filePaths.Count) As String
Dim i As Integer = 0
For Each filePath As XPathNavigator In filePaths
paths(i) = filePath.Value
Console.WriteLine(paths(i))
i = i + 1
Next
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/
Jul 29 '08 #4

P: n/a
Thanks for the info Steven. I had already implemented Martins approach.
However I have more XML reading coming up so this is sure to come into play.

Thanks for your time!

"Steven Cheng [MSFT]" <st*****@online.microsoft.comwrote in message
news:bO**************@TK2MSFTNGHUB02.phx.gbl...
Hi Justin,

From your description, you want to extract some certain values from an XML
document. In .net framework, there is quite rich API support for XML query
and processing. Here you have three different possible means to do it:

1. Use the xmlreader as you've tried, this is a memory efficient approahc,
but maybe more difficult to code(when xml is complex)

2. use XmlDocument + Xpath query, this is quite simple code

3. If you can use .NET 3.5, then "Linq to XML" is quite a good weapon you
can utilize

Here I've produced sample code (extracting the elements you want) for all
of the 3 approaches mentioned above:

===========using XML Reader================
private void btnReader_Click(object sender, EventArgs e)
{
StreamReader sr = new StreamReader(@"..\..\test.xml",
Encoding.UTF8);
XmlReader xr = XmlReader.Create(sr);

List<stringpaths = new List<string>();

while (xr.Read())
{
if (xr.IsStartElement("AppMode"))
{
MessageBox.Show(xr.GetAttribute("Type"));
}else if(xr.IsStartElement("CurrentFolder"))
{
MessageBox.Show(xr.GetAttribute("Path"));
}
else if (xr.IsStartElement("FilePath"))
{
paths.Add(xr.GetAttribute("Path"));
}
}

MessageBox.Show("paths count: " + paths.Count);
sr.Close();
}
=====================

========USE XML document + xpath query==============
private void btnXmlDoc_Click(object sender, EventArgs e)
{
XmlDocument doc = new XmlDocument();
doc.Load(@"..\..\test.xml");

string type =
doc.SelectSingleNode("/AppMode").Attributes["Type"].Value;
string curfolder =
doc.SelectSingleNode("/AppMode/CurrentFolder").Attributes["Path"].Value;

XmlNodeList files = doc.SelectNodes("//FilePath");

List<stringpaths = new List<string>();

foreach (XmlNode pnode in files)
{
paths.Add(pnode.InnerText);
}

MessageBox.Show("type: " + type + "\r\n"
+ "current folder: " + curfolder + "\r\n"
+ "paths count: " + paths.Count);
}
==============================

============ use LINQ TO XML ===================
private void btnLinq_Click(object sender, EventArgs e)
{
StreamReader sr = new StreamReader(@"..\..\test.xml",
Encoding.UTF8);
XDocument xdoc = XDocument.Load(sr);
sr.Close();
string type = xdoc.Element("AppMode").Attribute("Type").Value;
var cfs = from cf in xdoc.Descendants("CurrentFolder")
select cf.Attribute("Path").Value;

string curfolder = cfs.First();

var paths = from fp in xdoc.Descendants("FilePath")
select fp.Value;

List<stringfpaths = paths.ToList();

MessageBox.Show("type: " + type + "\r\n"
+ "current folder: " + curfolder + "\r\n"
+ "paths count: " + fpaths.Count);

}
=============================

if you want to know more about LINQ to XML, please have a look at the MSDN
reference:

#.NET Language-Integrated Query for XML Data
http://msdn.microsoft.com/en-us/library/bb308960.aspx

Sincerely,

Steven Cheng

Microsoft MSDN Online Support Lead
Delighting our customers is our #1 priority. We welcome your comments and
suggestions about how we can improve the support we provide to you. Please
feel free to let my manager know what you think of the level of service
provided. You can send feedback directly to my manager at:
ms****@microsoft.com.

==================================================
Get notification to my posts through email? Please refer to
http://msdn.microsoft.com/subscripti...ult.aspx#notif
ications.

Note: The MSDN Managed Newsgroup support offering is for non-urgent issues
where an initial response from the community or a Microsoft Support
Engineer within 1 business day is acceptable. Please note that each follow
up response may take approximately 2 business days as the support
professional working with you may need further investigation to reach the
most efficient resolution. The offering is not appropriate for situations
that require urgent, real-time or phone-based interactions or complex
project analysis and dump analysis issues. Issues of this nature are best
handled working with a dedicated Microsoft Support Engineer by contacting
Microsoft Customer Support Services (CSS) at
http://msdn.microsoft.com/subscripti...t/default.aspx.
==================================================
This posting is provided "AS IS" with no warranties, and confers no
rights.
--------------------
>>From: "Justin" <No**@None.com>
Subject: New to XML. Need help reading XML.
Date: Sat, 26 Jul 2008 00:24:30 -0700
>>
Here's my XML:

<?xml version="1.0" ?>
<AppMode Type="Network">
<CurrentFolder Path="c:\tabs">
<Tabs>
<FilePath>tabs\Justin.tab</FilePath>
<FilePath>tabs\Julie.tab</FilePath>
*****There could be 1 of these or 100....quantity can change*****
</Tabs>
</CurrentFolder>
</AppMode>
All I need to do is load "Network" and "c:\tabs" into variables. Then
each
>>FilePath goes into an array.

The following code gives me everything but Julie.tab. It only gives me
one
>>of the FilePaths. I'm not even sure if this is the right/best way to do
this:

Dim XMLReader As XmlTextReader = New XmlTextReader("")
XMLReader.WhitespaceHandling = WhitespaceHandling.None

XMLReader.Read()
XMLReader.Read()
MsgBox(XMLReader.GetAttribute("Type"))

XMLReader.Read()
MsgBox(XMLReader.GetAttribute("Path"))

XMLReader.Read()

While Not XMLReader.EOF *****Why isn't this looping?

XMLReader.Read()

If Not XMLReader.IsStartElement() Then
Exit While
End If

MsgBox(XMLReader.ReadElementString("FilePath"))

End While

XMLReader.Close()

Any help would be greatly appreciated!

Jul 29 '08 #5

P: n/a
Thanks for your reply Justin,

No problem. If you need any help on this later, please feel free to post
here.

Sincerely,

Steven Cheng

Microsoft MSDN Online Support Lead
Delighting our customers is our #1 priority. We welcome your comments and
suggestions about how we can improve the support we provide to you. Please
feel free to let my manager know what you think of the level of service
provided. You can send feedback directly to my manager at:
ms****@microsoft.com.

==================================================
Get notification to my posts through email? Please refer to
http://msdn.microsoft.com/subscripti...ult.aspx#notif
ications.
==================================================
This posting is provided "AS IS" with no warranties, and confers no rights.

--------------------
>From: "Justin" <No**@None.com>
References: <#J**************@TK2MSFTNGP04.phx.gbl>
<bO**************@TK2MSFTNGHUB02.phx.gbl>
>Subject: Re: New to XML. Need help reading XML.
Date: Mon, 28 Jul 2008 21:50:27 -0700
>Thanks for the info Steven. I had already implemented Martins approach.
However I have more XML reading coming up so this is sure to come into
play.
>
Thanks for your time!

"Steven Cheng [MSFT]" <st*****@online.microsoft.comwrote in message
news:bO**************@TK2MSFTNGHUB02.phx.gbl...
>Hi Justin,

From your description, you want to extract some certain values from an
XML
>document. In .net framework, there is quite rich API support for XML
query
>and processing. Here you have three different possible means to do it:

1. Use the xmlreader as you've tried, this is a memory efficient
approahc,
>but maybe more difficult to code(when xml is complex)

2. use XmlDocument + Xpath query, this is quite simple code

3. If you can use .NET 3.5, then "Linq to XML" is quite a good weapon you
can utilize

Here I've produced sample code (extracting the elements you want) for all
of the 3 approaches mentioned above:

===========using XML Reader================
private void btnReader_Click(object sender, EventArgs e)
{
StreamReader sr = new StreamReader(@"..\..\test.xml",
Encoding.UTF8);
XmlReader xr = XmlReader.Create(sr);

List<stringpaths = new List<string>();

while (xr.Read())
{
if (xr.IsStartElement("AppMode"))
{
MessageBox.Show(xr.GetAttribute("Type"));
}else if(xr.IsStartElement("CurrentFolder"))
{
MessageBox.Show(xr.GetAttribute("Path"));
}
else if (xr.IsStartElement("FilePath"))
{
paths.Add(xr.GetAttribute("Path"));
}
}

MessageBox.Show("paths count: " + paths.Count);
sr.Close();
}
=====================

========USE XML document + xpath query==============
private void btnXmlDoc_Click(object sender, EventArgs e)
{
XmlDocument doc = new XmlDocument();
doc.Load(@"..\..\test.xml");

string type =
doc.SelectSingleNode("/AppMode").Attributes["Type"].Value;
string curfolder =
doc.SelectSingleNode("/AppMode/CurrentFolder").Attributes["Path"].Value;

XmlNodeList files = doc.SelectNodes("//FilePath");

List<stringpaths = new List<string>();

foreach (XmlNode pnode in files)
{
paths.Add(pnode.InnerText);
}

MessageBox.Show("type: " + type + "\r\n"
+ "current folder: " + curfolder + "\r\n"
+ "paths count: " + paths.Count);
}
==============================
Jul 29 '08 #6

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