467,911 Members | 1,375 Online
Bytes | Developer Community
New Post

Home Posts Topics Members FAQ

Post your question to a community of 467,911 developers. It's quick & easy.

what's wrong with xml post code?

Hi
Trying to get this code to work for http xml post.
I need the post to be xml (doc.outerxml) sent in single key name as stream.
The following is the post code and code for receiving the request.
When it hits the "myresponse = myrequest.GetResponse()" in the post code -
I'm getting following error:
"The remote server returned an error: (500) Internal Server Error".
I don't know if I have something wrong with the post or receiving it on the
other end.
Right now I'm trying to write it in .net 1.1.
Any help will be greatly appreciated.
Thanks,
Cindy

Dim url As String = "http://someplace.aspx"
Dim myrequest As System.Net.WebRequest = Nothing
Dim myresponse As System.Net.WebResponse = Nothing
Try
' Create a request using a URL that can receive a post.
myrequest = System.Net.WebRequest.Create(url)
' Set the Method property of the request to POST.
myrequest.Method = "POST"
' Set the ContentType property of the WebRequest.
myrequest.ContentType = "application/x-www-form-urlencoded"
' Create POST data and convert it to a byte array.
Dim vxml = "Interface_2=" + HttpUtility.UrlEncode(Doc.OuterXml)
Dim byteArray As Byte() =
System.Text.Encoding.UTF8.GetBytes(vxml)
' Set the ContentLength property of the WebRequest.
myrequest.ContentLength = byteArray.Length
' Get the request stream.
Dim dataStream As System.io.Stream =
myrequest.GetRequestStream()
' Write the data to the request stream.
dataStream.Write(byteArray, 0, byteArray.Length)
' Close the Stream object.
dataStream.Close()
' Get the response.
myresponse = myrequest.GetResponse() 'error occurs here
Catch ex As Exception
Throw ex
Finally
' Closed streams
If Not myrequest Is Nothing Then
myrequest.GetRequestStream().Close()
If Not myresponse Is Nothing Then
myresponse.GetResponseStream().Close()
End Try

Code for receiving the post:
Dim strReader As System.IO.StringReader = Nothing
Dim Reader As System.Xml.XmlTextReader = Nothing
Response.ContentType = "application/x-www-form-urlencoded"
Response.Clear()
Try
strReader = New
System.IO.StringReader(Request.Form("Interface_2") )
Reader = New System.Xml.XmlTextReader(strReader)
Do While Reader.Read()
Jun 27 '08 #1
  • viewed: 2026
Share:
2 Replies
* CindyH wrote in microsoft.public.dotnet.xml:
>Trying to get this code to work for http xml post.
I need the post to be xml (doc.outerxml) sent in single key name as stream.
The following is the post code and code for receiving the request.
When it hits the "myresponse = myrequest.GetResponse()" in the post code -
I'm getting following error:
"The remote server returned an error: (500) Internal Server Error".
This means something has gone wrong on the server. It's quite possible
that this is a result of an error on your side, but without checking the
server (e.g., the logs, read source code of the remote application) it's
not possible to know for sure. You don't say, for example, whether this
works fine when using some other application to access the resource.
--
Björn Höhrmann · mailto:bj****@hoehrmann.de · http://bjoern.hoehrmann.de
Weinh. Str. 22 · Telefon: +49(0)621/4309674 · http://www.bjoernsworld.de
68309 Mannheim · PGP Pub. KeyID: 0xA4357E78 · http://www.websitedev.de/
Jun 27 '08 #2
I'm using xmlreader, not a xmltextreader and moved it to .net 2.0, but still
no luck.

"CindyH" <ch*******@new.rr.comwrote in message
news:%2****************@TK2MSFTNGP03.phx.gbl...
Hi
Trying to get this code to work for http xml post.
I need the post to be xml (doc.outerxml) sent in single key name as
stream.
The following is the post code and code for receiving the request.
When it hits the "myresponse = myrequest.GetResponse()" in the post code -
I'm getting following error:
"The remote server returned an error: (500) Internal Server Error".
I don't know if I have something wrong with the post or receiving it on
the other end.
Right now I'm trying to write it in .net 1.1.
Any help will be greatly appreciated.
Thanks,
Cindy

Dim url As String = "http://someplace.aspx"
Dim myrequest As System.Net.WebRequest = Nothing
Dim myresponse As System.Net.WebResponse = Nothing
Try
' Create a request using a URL that can receive a post.
myrequest = System.Net.WebRequest.Create(url)
' Set the Method property of the request to POST.
myrequest.Method = "POST"
' Set the ContentType property of the WebRequest.
myrequest.ContentType = "application/x-www-form-urlencoded"
' Create POST data and convert it to a byte array.
Dim vxml = "Interface_2=" + HttpUtility.UrlEncode(Doc.OuterXml)
Dim byteArray As Byte() =
System.Text.Encoding.UTF8.GetBytes(vxml)
' Set the ContentLength property of the WebRequest.
myrequest.ContentLength = byteArray.Length
' Get the request stream.
Dim dataStream As System.io.Stream =
myrequest.GetRequestStream()
' Write the data to the request stream.
dataStream.Write(byteArray, 0, byteArray.Length)
' Close the Stream object.
dataStream.Close()
' Get the response.
myresponse = myrequest.GetResponse() 'error occurs here
Catch ex As Exception
Throw ex
Finally
' Closed streams
If Not myrequest Is Nothing Then
myrequest.GetRequestStream().Close()
If Not myresponse Is Nothing Then
myresponse.GetResponseStream().Close()
End Try

Code for receiving the post:
Dim strReader As System.IO.StringReader = Nothing
Dim Reader As System.Xml.XmlTextReader = Nothing
Response.ContentType = "application/x-www-form-urlencoded"
Response.Clear()
Try
strReader = New
System.IO.StringReader(Request.Form("Interface_2") )
Reader = New System.Xml.XmlTextReader(strReader)
Do While Reader.Read()

Jun 27 '08 #3

This discussion thread is closed

Replies have been disabled for this discussion.

Similar topics

46 posts views Thread by Keith K | last post: by
13 posts views Thread by Jason Huang | last post: by
5 posts views Thread by Joey | last post: by
28 posts views Thread by federico_bertola | last post: by
10 posts views Thread by Enkidu | last post: by
2 posts views Thread by CindyH | last post: by
By using this site, you agree to our Privacy Policy and Terms of Use.