How to represent '&' as a variable in xslt file

[ofuuzo1]

Hi,

I have tried the following but it do not work:

<xsl:variable name="path1" select="string('&')"/>
<xsl:variable name="path1" select="string('&')"/>
<xsl:variable name="path1" select="&"/>

Thanks in advance
Ofuuzo

[Martin Honnen]

of*****@yahoo.no wrote:

I have tried the following but it do not work:

<xsl:variable name="path1" select="string('&')"/>

<xsl:variable name="path1" select="'&amp;'"/>


--

Martin Honnen
http://JavaScript.FAQTs.com/

[Joseph J. Kesselman]

Martin Honnen wrote:

<xsl:variable name="path1" select="'&amp;'"/>

That should be equivalent to select="'&'", of course.

(The trick here is the double-quoting. Select is interpreted as an
XPath... and the XPath syntax wants its own layer of quotes to indicate
that you're trying to express a literal value.)

[Richard Tobin]

In article <a3**********************************@d1g2000hsg.g ooglegroups.com>,
<of*****@yahoo.nowrote:

><xsl:variable name="path1" select="string('&')"/>
<xsl:variable name="path1" select="&"/>

Those won't work because they're not well-formed XML.

><xsl:variable name="path1" select="string('&')"/>

That should work: what error do you get?

The simplest solution is

<xsl:variable name="path1" select="'&'"/>

-- Richard
--
:wq