C# typecast Int to Double

[SpecialKay]

This might be an eazy problem to fix,
assume all works except the int to double

double total = 0;
double Qty[10];
 
int price[10];
 
for(int i = 0; i < 9; i++)
{
 total += Qty[i] * (double)price[i];
}
 
 

i need to get total in the forme of a double.
any ideas?

[Plater]

EDIT:
Actually, I think your example might be a little off. Wouldn't you want price to be a double and quantity to be the int? Your array declarations seemed to be off as well, since those aren't valid declarations.

I just did this, without typecasting at all and total stayed a double:

double total = 0;
            double[] Qty = new double[10];
            Qty[0] = 1.1;
            Qty[1] = 4.5;
            Qty[2] = 9.7;
            Qty[3] = 2.6;
            Qty[4] = 0.7;
 
            int[] price = new int[10];
            price[0] = 1;
            price[1] = 4;
            price[2] = 3;
            price[3] = 7;
 
            for (int i = 0; i < 9; i++)
            {
                total += Qty[i] * price[i];
            }
 

Total was a double just fine. So I am thinking in your ACTUAL code there is something else wrong?

[SpecialKay]

here is the Accualy code

            infos.TotalCost += (double)(infos.Order.OrderLineItemCollection[i - 1].Quantity * double.Parse(infos.Order.OrderLineItemCollection[i - 1].Price));
 
 

broken down

infos.TotalCost = Double
infos.Order.OrderLineItemCollection[i - 1].Quantity -> Returns int
infos.Order.OrderLineItemCollection[i - 1].Price -> returns String (double.Parse works for this)
 
 

[Plater]

Your actual code looks like it should work fine?

[SpecialKay]

Ya i agree, there must be a problem somewhere else.
im going to snoop around and see what i come up with.
In other news:

if you multiply an int (2) by a double (1.3) into a double like

double ans = 0;
int a = 2;
double b = 1.3;
 
ans = a*b;
 
does ans become an int?
what would the value of ans be?
 

[Plater]

It should be a double.
You can run all these testcases yourself to see the answer quickly though.

[SpecialKay]

you are write :)
thanks tho, i did after i posted the question, so i really didnt need to post it. but o well.