now to set line endings with XSLT

[Andy Fish]

Hi,

I am using .Net 2.0 XslCompiledTransform with output method=text.

it seems to be converting all the line endings in the output to cr/lf
regardless of how I generate them. for instance, this fragment

<xsl:text>|&#xd;|&#xd;&#xa;|&#xa;|<xsl:text>

generates |<crlf>|<crlf>|<crlf>|

any idea how I can control the line endings generated by the XSLT processor?

TIA

Andy

[Martin Honnen]

Andy Fish wrote:

any idea how I can control the line endings generated by the XSLT
processor?

I am not sure there is a way other than post-processing the result of
the XSLT transformation.

--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

[Andy Fish]

FWIW I found out you can do it using XmlWriterSettings.NewLineChars or
XmlWriterSettings.NewLineHandling. here's a sample:

XslCompiledTransform trans = new XslCompiledTransform();
trans.Load(...);
XmlWriterSettings ws = trans.OutputSettings.Clone();
ws.NewLineChars = '\n';
using (XmlWriter xw = XmlWriter.Create(..., ws))
{
trans.Transform(..., xw);
}

Andy
"Martin Honnen" <ma*******@yahoo.dewrote in message
news:eA**************@TK2MSFTNGP04.phx.gbl...

Andy Fish wrote:

>any idea how I can control the line endings generated by the XSLT
processor?

I am not sure there is a way other than post-processing the result of the
XSLT transformation.

--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

[Martin Honnen]

Andy Fish wrote:

FWIW I found out you can do it using XmlWriterSettings.NewLineChars or
XmlWriterSettings.NewLineHandling. here's a sample:

XslCompiledTransform trans = new XslCompiledTransform();
trans.Load(...);
XmlWriterSettings ws = trans.OutputSettings.Clone();
ws.NewLineChars = '\n';

Nice. I tried settings NewLineChars too but did not clone it and then
the properties were read-only and my attempts failed.

--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/