xslt: continue in for-each-group?

[bbembi_de]

Hello everyone,

I have just a little xslt problem:

<xsl:for-each-group select="item" group-by="name">
<xsl:if test="contains(name, 'teststring11')">
<xsl:apply-templates select="current-group()"/>
</xsl:if>
<xsl:if test="contains(name, 'teststring22')">
<xsl:apply-templates select="current-group()"/>
</xsl:if>
</xsl:for-each-group>

This xslt is fine, but has 1 problem: I want to make a "continue" in
my if clauses. If the program walks into a if clause it should go to
the next for-each-group. I don't want every if clause to be executed,
only one.

How can I do that?

Thanks very much.

bye bembi

[Alain Ketterlin]

"bb*******@lycos.de" <bb*******@lycos.dewrites:

I have just a little xslt problem:

<xsl:for-each-group select="item" group-by="name">
<xsl:if test="contains(name, 'teststring11')">
<xsl:apply-templates select="current-group()"/>
</xsl:if>
<xsl:if test="contains(name, 'teststring22')">
<xsl:apply-templates select="current-group()"/>
</xsl:if>
</xsl:for-each-group>

This xslt is fine, but has 1 problem: I want to make a "continue" in
my if clauses. If the program walks into a if clause it should go to
the next for-each-group. I don't want every if clause to be executed,
only one.

How can I do that?

<xsl:choose?

-- Alain.

[Joseph Kesselman]

I presume you've already looked at all the grouping techniques in

http://www.dpawson.co.uk/xsl/sect2/N4486.html
http://www.dpawson.co.uk/xsl/sect2/N6280.html

--
Joe Kesselman / Beware the fury of a patient man. -- John Dryden

[Martin Honnen]

bb*******@lycos.de wrote:

Thanks very much for the info.

Now I found out what my real problem is (I tried xsl:choose before
writing the first mail):

I have a xml like this:

<root>
<item name="111">
<subitem name="aaa">
<subitem name="bbb">
</item>....

I group the subitems but only want to output a item name once.
I want only one item output.

<xsl:for-each-group select="subitem" group-by="name">
<xsl:apply-templates select="current-group()" //here I output
the name of the parent (item) but this should be only once for every
item.

I am not sure I understand what you want to achieve, your sample has
just one item element having two subitem children with an attribute
named 'name' which has different values so there is not much to group
by. And your XPath does group-by="name", if you want to group on the
attribute you need group-by="@name".
Can you show us enough XML sample data that it becomes clear what you
want to group?

--

Martin Honnen
http://JavaScript.FAQTs.com/

[bbembi_de]

Hello again,

given the following xml:
<root>
<item name="111">
<subitem name="aaa">
<subitem name="bbb">
<subitem name="ccc">
</item>
<item name="222">
<subitem name="ccc">
<subitem name="bbb">
</item>

If i want all item names that have the subitems aaa and ccc I want the
output:
111

but currently I get the output:
111
111

How can I do this?

thanks bembi


On 7 Feb., 17:12, Martin Honnen <[e-mail]:

[e-mail] wrote:

Thanks very much for the info.

Now I found out what my real problem is (I triedxsl:choose before
writing the first mail):

I have a xml like this:

<root>
<item name="111">
<subitem name="aaa">
<subitem name="bbb">
</item>....

I group the subitems but only want to output a item name once.
I want only one item output.

<xsl:for-each-group select="subitem" group-by="name">
<xsl:apply-templates select="current-group()" //here I output
the name of the parent (item) but this should be only once for every
item.

I am not sure I understand what you want to achieve, your sample has
just one item element having two subitem children with an attribute
named 'name' which has different values so there is not much to group
by. And your XPath does group-by="name", if you want to group on the
attribute you need group-by="@name".
Can you show us enough XML sample data that it becomes clear what you
want to group?

--

Martin Honnen
http://JavaScript.FAQTs.com/

[Joseph Kesselman]

You haven't shown your code, but this sounds like a simple matter of
rewriting the test...

--
Joe Kesselman / Beware the fury of a patient man. -- John Dryden