Hello everyone,
I think printf %d works fine with signed, unsigned and negative integer
values, and the same as %ld for long. Is that correct? If not, do we need to
special conversion?
thanks in advance,
George
4  3989 
George wrote:
Hello everyone,
I think printf %d works fine with signed, unsigned and negative integer
values, and the same as %ld for long. Is that correct? If not, do we need to
special conversion?
George:
%d will only work for unsigned int if the value is not bigger than the
largest allowed value of int. Otherwise, a negative value will be displayed.
--
David Wilkinson
Visual C++ MVP
Hi David,
Only works for unsigned int? I have tried that -1 works. :-)
int i = -1;
printf ("i is: %d", -1);
I have tried it on Visual Studio 2005.
regards,
George
"David Wilkinson" wrote:
George wrote:
Hello everyone,
I think printf %d works fine with signed, unsigned and negative integer
values, and the same as %ld for long. Is that correct? If not, do we need to
special conversion?
George:
%d will only work for unsigned int if the value is not bigger than the
largest allowed value of int. Otherwise, a negative value will be displayed.
--
David Wilkinson
Visual C++ MVP
George wrote:
Hi David,
Only works for unsigned int? I have tried that -1 works. :-)
int i = -1;
printf ("i is: %d", -1);
I have tried it on Visual Studio 2005.
regards,
George
"David Wilkinson" wrote:
>%d will only work for unsigned int if the value is not bigger than the
largest allowed value of int. Otherwise, a negative value will be displayed.
--
David Wilkinson
Visual C++ MVP
George:
I meant:
For unsigned int, %d will only work if the value is not bigger than the
largest allowed value of int. Otherwise, a negative value will be
displayed. %u should be used with unsigned int.
%d is intended for use with int, and either positive or negative values
may be displayed.
Although not so well suited to localization, C++ streams handle this
issue much better, because they are overloaded for different types.
--
David Wilkinson
Visual C++ MVP
Thanks David,
I agree.
regards,
George
"David Wilkinson" wrote:
George wrote:
Hi David,
Only works for unsigned int? I have tried that -1 works. :-)
int i = -1;
printf ("i is: %d", -1);
I have tried it on Visual Studio 2005.
regards,
George
"David Wilkinson" wrote:
%d will only work for unsigned int if the value is not bigger than the
largest allowed value of int. Otherwise, a negative value will be displayed.
--
David Wilkinson
Visual C++ MVP
George:
I meant:
For unsigned int, %d will only work if the value is not bigger than the
largest allowed value of int. Otherwise, a negative value will be
displayed. %u should be used with unsigned int.
%d is intended for use with int, and either positive or negative values
may be displayed.
Although not so well suited to localization, C++ streams handle this
issue much better, because they are overloaded for different types.
--
David Wilkinson
Visual C++ MVP
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