How to open a image which is stored in server

[rohitbce]

Hi
I am saved my Document in server By the follwing code

coding............


If fupLoadDoc.HasFile Then
Dim reader As BinaryReader = New BinaryReader(fupLoadDoc.PostedFile.InputStream)
Dim byt() As Byte = reader.ReadBytes(fupLoadDoc.PostedFile.ContentLeng th)
''objVLEAttacheDoc.Documentimg = byt
dtDoc.Rows(intrr).Item(3) = byt
objVLEAttacheDoc.Documentimg = dtDoc.Rows(intrr).Item(3)
Else
dtDoc.Rows(intrr).Item(3) = System.DBNull.Value
objVLEAttacheDoc.Documentimg = dtDoc.Rows(intrr).Item(3)
End If

This save the Document on the server successfully
now problem is that i want to open that document
so how can i ................
plz help me.............................
Rohit Jain

[rohitbce]

its Urgent plz help me
Rohit

[Shashi Sadasivan]

I havent done this, but u need to convert the bytestream (the blob) back to an image type...
have you searched for anything similar?

got something which might be of interest to you

OracleBlob blob = reader.GetOracleBlob(0);
 
Bitmap image = new Bitmap(blob);
pictureBox1.Image=image;

cheers

[rohitbce]

I havent done this, but u need to convert the bytestream (the blob) back to an image type...
have you searched for anything similar?

got something which might be of interest to you

OracleBlob blob = reader.GetOracleBlob(0);
 
Bitmap image = new Bitmap(blob);
pictureBox1.Image=image;

cheers

Thanks for your valuable response
i am useing sql and convert it like that but not getting how to get the path
Session("txtscan") = ObjData1.Tables(0).Rows(IntCounter1).Item(0)
Dim byt() As Byte = CType(ObjData1.Tables(0).Rows(IntCounter1).Item(0) , Byte())
Dim bmpimg As Bitmap
Dim mstream As New MemoryStream
mstream.Write(byt, 0, byt.Length)
I am not using any picture box instead of this i am using like an website we open the attachment i have done like that that working but when i am open a file from server it's not working ...............


Dim TargetFile As FileInfo
TargetFile = New System.IO.FileInfo(ViewState("Path"))
Response.Clear()

Response.AddHeader("Content-Disposition", "attachment; filename=" + TargetFile.Name)

Response.AddHeader("Content-Length", TargetFile.Length.ToString())

Response.WriteFile(TargetFile.FullName)

Response.End()
Rohit