Hpw to know level tag position

[sam]

I need to know a way for knowing tag position in a xml like this:

<AAA>
<BBB>
<CCC>
<DDD_1/>
<DDD_2/>
<DDD_3/>
</CCC>
<BBB/>
</AAA>
I need to get that AAA = 1, BBB=2,CCC=3,
DDD_1=4, DDD_2=4,DDD_3=4

thanks for help.
Sam

[Martin Honnen]

sam wrote:

I need to know a way for knowing tag position in a xml like this:

<AAA>
<BBB>
<CCC>
<DDD_1/>
<DDD_2/>
<DDD_3/>
</CCC>
<BBB/>
</AAA>
I need to get that AAA = 1, BBB=2,CCC=3,
DDD_1=4, DDD_2=4,DDD_3=4

count($n/ancestor::node()) where $n is your node. So with a stylesheet
you could do:

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xsl:output method="text"/>

<xsl:template match="/">
<xsl:apply-templates select="//*"/>
</xsl:template>

<xsl:template match="*">
<xsl:value-of select="concat(name(), ' = ',
count(./ancestor::node()))"/>
<xsl:if test="position() != last()"><xsl:text>, </xsl:text></xsl:if>
</xsl:template>

</xsl:stylesheet>
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

[sam]

Martin Honnen

count($n/ancestor::node()) where $n is your node. So with a stylesheet

Okey, but I am using XML .Net control for handling xml files.
So, how to get this value in csharp code ?

Sam

"Martin Honnen" <ma*******@yahoo.dea écrit dans le message de news:
Or**************@TK2MSFTNGP04.phx.gbl...

sam wrote:

>I need to know a way for knowing tag position in a xml like this:

<AAA>
<BBB>
<CCC>
<DDD_1/>
<DDD_2/>
<DDD_3/>
</CCC>
<BBB/>
</AAA>
I need to get that AAA = 1, BBB=2,CCC=3,
DDD_1=4, DDD_2=4,DDD_3=4

count($n/ancestor::node()) where $n is your node. So with a stylesheet you
could do:

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xsl:output method="text"/>

<xsl:template match="/">
<xsl:apply-templates select="//*"/>
</xsl:template>

<xsl:template match="*">
<xsl:value-of select="concat(name(), ' = ',
count(./ancestor::node()))"/>
<xsl:if test="position() != last()"><xsl:text>, </xsl:text></xsl:if>
</xsl:template>

</xsl:stylesheet>
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

[sam]

Martin, thank you very very very much for all samples that works fine.

Sam