Getting the x:y coordinates of the PictureBox Image

[Andrzej]

I have a picturebox on my C# .NET form. The picturebox size mode is set to
zoom. I then load an image into that form and display it. As the user
moves the mouse over the form, I want to get and display (in the status bar)
the image coordinates of the mouse location. However, if I use the
picturebox's MouseMove event, I am getting the coordinates of the mouse over
the PICTUREBOX, not the actual image underneath that (which is zoomed).
i.e. if the actual image has a width of 2000, and I move the cursor over to
the right side of the zoomed picturebox image, I am only getting a left
pixel value of around 1000 - because it is getting the mouse x:y coordinates
of the picture box, not the actual image.

How can I accomplish this? There isn't any picturebox.image.mousemove event
that I can see. How can I translate what the picturebox gives me back to the
coordinates of the actual image underneath it? Or have I got to go about
this differently?

Andrzej [email removed]

[kenobewan]

Here is a thread that may help:
Get Mouse coordinates of Image in PictureBox

[shweta123]

Hi,

Please refer this Link

[Megadardery]

Put this in MouseMove of the PictureBox:

//Declarations of few variables to minimize the number of refers to the Picture Box.
 
{
    int imgWidth = PictureBox1.Image.Width;
    int imgHeight = PictureBox1.Image.Height;
    int boxWidth = PictureBox1.Size.Width;
    int boxHeight = PictureBox1.Size.Height;
 
    //This variable will hold the result
    float X = e.X;
    float Y = e.Y;
    //Comparing the aspect ratio of both the control and the image itself.
    if (imgWidth / imgHeight > boxWidth / boxHeight) {
        //If true, that means that the image is stretched through the width of the control.
        //'In other words: the image is limited by the width.
 
        //The scale of the image in the Picture Box.
        float scale = boxWidth / imgWidth;
 
        //Since the image is in the middle, this code is used to determinate the empty space in the height
        //'by getting the difference between the box height and the image actual displayed height and dividing it by 2.
        float blankPart = (boxHeight - scale * imgHeight) / 2;
 
        Y -= blankPart;
 
        //Scaling the results.
        X /= scale;
        Y /= scale;
    } else {
        //If true, that means that the image is stretched through the height of the control.
        //'In other words: the image is limited by the height.
 
        //The scale of the image in the Picture Box.
        float scale = boxHeight / imgHeight;
 
        //Since the image is in the middle, this code is used to determinate the empty space in the width
        //'by getting the difference between the box width and the image actual displayed width and dividing it by 2.
        float blankPart = (boxWidth - scale * imgWidth) / 2;
        X -= blankPart;
 
        //Scaling the results.
        X /= scale;
        Y /= scale;
    }
    Label1.Text = Conversion.Int(X) + ", " + Conversion.Int(Y);
}