Openfile dialogue and datagrid

[jaeden99]

I have created a datagrid filled with information from the database. When a user clicks on a particular cell (this cell contains drive letter and file name), I would like to be able to open the file. I have the datagrid cell selection code complete however when the openfiledialog appears, the filename showing in the filename box is openfiledialog1. How do I get the filename to be the actual selection from the datagrid cell. See code below:

'MessageBox.Show("Row " & e.RowIndex.ToString() & " and column " & e.ColumnIndex.ToString())
        Dim hit As String
        'Dim fileNm As File
 
        Dim m_inputstream As IO.StreamReader
 
        If e.Button = Windows.Forms.MouseButtons.Right AndAlso e.RowIndex >= 0 Then
            DataGridView1.Rows(e.RowIndex).Selected = True
 
            'configure the dialog 
            With OpenFileDialog1
                .InitialDirectory = "C:"
                .Filter = "All Files (*.*)|*.*"
                .CheckFileExists = True
                TextBox1.Text = (DataGridView1.SelectedCells(0).Value.ToString())
                hit = TextBox1.Text
                TextBox1.Text = (DataGridView1.SelectedCells(0).Value.ToString())
                hit = TextBox1.Text
 
                'open Dialiog
                If .ShowDialog = Windows.Forms.DialogResult.OK Then
                    'm_InputStream = CType(OpenFileDialog1.OpenFile(), System.IO.StreamReader)
                    m_inputstream = New System.IO.StreamReader(OpenFileDialog1.OpenFile)
                    If m_inputstream Is Nothing Then
                        Throw New Exception("Error opeing the file")
                    End If
 
                    'OpenFileDialog1.OpenFile.ToString(filNm)
 
 
                End If
            End With