Xpath and XSLT-transformation problem

[Pathik]

Hi All,

Currently I am trying to convert one xml file into another xml file
which having different format than original xml file.

my input xml file is like:

<?xml version="1.0" encoding="UTF-8"?>
<MyData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:n1="http://www.abc.com/resources/XML/schemas/v2_0">

<header>
<id>1</id>
<test>xyz</test>
</header>
<n1:DataSet>
<n1:Group REF="SE" ADJ="N"
ABC_I="PROD" ABC_A="N100C0" ABC_IN="1"
ABC_B_Y="2000"/>
<n1:Series FR="M" REF="SE" ADJ="N"
ABC_I="PROD" ABC_A="N100C0" ABC_IN="1"
ABC_B_Y="2000">
<n1:Obs TIME_P="199001" OBS_VALUE="101.2"/>
<n1:Obs TIME_P="199002" OBS_VALUE="103.2"/>
<n1:Obs TIME_P="199003" OBS_VALUE="105.2"/>
<n1:Obs TIME_P="199004" OBS_VALUE="107.2"/>
</n1:Series>
</n1:DataSet>
</MyData>

I have to extract the Series element based on the values of ADJ,ABC_A
etc.My intend is more clear from the following xsl file:
The problem is that in xpath expression it doesn't recognizing
namespace elements ie elements prefixed with n1

Please check this and let me know where i am doing wrong.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/
Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:n1="http://www.abc.com/resources/XML/schemas/v2_0">

<xsl:output method="xml" encoding="UTF-8" indent="yes"/>

<xsl:param name="REF"/>
<xsl:param name="ADJ"/>
<xsl:param name="ABC_I"/>
<xsl:param name="ABC_A"/>
<xsl:param name="ABC_IN"/>
<xsl:param name="ABC_B_Y"/>
<xsl:template match="/">

<Data>
<Table language="en">
<Info>
</Info>
<Nomenclatures>
</Nomenclatures>
<Context>
<Selector type="theme" code="theme1"/>
<Selector type="domain" code="euro"/>
<Selector type="table" code="bp_q"/>
</Context>
<Grid>

<AxisZ name="REF">
<xsl:for-each
select="MyData/n1:DataSet/n1:Series[
@ADJ=$ADJ and
@ABC_A=$ABC_A and
@ABC_IN=$ABC_I and
@ABC_B_Y=$ABC_B_Y]">
<xsl:element name="Position">
<xsl:attribute name="value">
<xsl:value-of select="@REF"/>
</xsl:attribute>
</xsl:element>
<AxisY name="STS_INDICATOR">
<xsl:element name="Position">
<xsl:attribute name="value">
<xsl:value-of select="@ABC_IN"/>
</xsl:attribute>
</xsl:element>
<AxisX name="time">
<xsl:for-each select="./n1:Obs">
<xsl:element name="Position">
<xsl:attribute name="value">
<xsl:value-of
select="@TIME_P"/>
</xsl:attribute>
</xsl:element>
<xsl:element name="Cell">
<xsl:attribute name="value">
<xsl:value-of
select="@OBS_VALUE"/>
</xsl:attribute>
</xsl:element>
</xsl:for-each>
</AxisX>
</AxisY>
</xsl:for-each>
</AxisZ>
</Grid>

</Table>
</Data>
</xsl:template>
</xsl:stylesheet>

Thanks and Regards,
Pathik

[p.lepin]

On Mar 30, 8:26 am, "Pathik" <[e-mail]>
wrote:

my input xml file is like:

[skipped]

My intend is more clear from the following xsl file:

You've gotta be kidding. You're using 8 spaces for
indentation and you've obviously never heard of the 78
chars rule. Worse yet, this is a brilliant example of how
NOT to write XSL transformations. The thing is horrible and
you think it makes anything 'more clear'?

The problem is that in xpath expression it doesn't
recognizing namespace elements ie elements prefixed with
n1

Wonderful. What makes you think that?

<xsl:for-each
select="MyData/n1:DataSet/n1:Series[
@ADJ=$ADJ and
@ABC_A=$ABC_A and
@ABC_IN=$ABC_I and
@ABC_B_Y=$ABC_B_Y]">

I would strongly recommend learning some basic debugging
techniques. (Hint: there's an error in this bit of code.)

(Note: looking at awful code and pointing straight at the
bug is something I normally charge for on per-hour basis.
You get answers to smart and thought-provoking questions
for free; do not expect people to do your bloody job for
you. Keep that in mind.)

--
Pavel Lepin