problem with xslt transformation

Pathik

Hi All,

I am New to xml. Currently I am trying to transform one xml file to
another file using xslt

my xml file is as follows:

<?xml version="1.0" encoding="UTF-8" ?>
<?xml-stylesheet type="text/xml" href="test.xsl" version="2.0"?>
<Data>
<Header>
<ID>JD014</ID>
<Test>true</Test>
</Header>
</Data>

and xsl file is as follows:test.xsl

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/
Transform">
<xsl:template match="/">
<xsl:for-each select="Header">
<xsl:value-of select="ID"></xsl:value-of>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

I m trying to print the value of ID in output . But instead of
transformation Internet explorer simply
shows input file as it is.

Please check this and let me know where i am wrong.

Thanks and Regards,
Pathik

Mar 27 '07 #1

Subscribe Post Reply

2010

Bjoern Hoehrmann

* Pathik wrote in comp.text.xml:

>Hi All,

I am New to xml. Currently I am trying to transform one xml file to
another file using xslt

my xml file is as follows:

<?xml version="1.0" encoding="UTF-8" ?>
<?xml-stylesheet type="text/xml" href="test.xsl" version="2.0"?>
<Data>
<Header>
<ID>JD014</ID>
<Test>true</Test>
</Header>
</Data>

and xsl file is as follows:test.xsl

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/
Transform">
<xsl:template match="/">
<xsl:for-each select="Header">
<xsl:value-of select="ID"></xsl:value-of>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

I m trying to print the value of ID in output . But instead of
transformation Internet explorer simply
shows input file as it is.

Internet Explorer does not support XSLT 2.0 and the xml-stylesheet
processing instruction does not have a version pseudo-attribute.
Further, <xsl:template match="/"matches the document node, not
the root element node, so your for-each would select no nodes as
there are no "Header" elements that are children of the document
node.
--
Björn Höhrmann · mailto:bj****@hoehrmann.de · http://bjoern.hoehrmann.de
Weinh. Str. 22 · Telefon: +49(0)621/4309674 · http://www.bjoernsworld.de
68309 Mannheim · PGP Pub. KeyID: 0xA4357E78 · http://www.websitedev.de/

Mar 27 '07 #2

Martin Honnen

Pathik wrote:

<Data>
<Header>
<ID>JD014</ID>
<Test>true</Test>
</Header>
</Data>

and xsl file is as follows:test.xsl

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/

^^^^^^^^^^^^^
Use version="1.0" for IE or other browsers as XSLT 2.0 is too new to be
supported by browsers. While the XSLT processor will try to process the
stylesheet even for a not supported version (so called forwards
compatible processsing <http://www.w3.org/TR/xslt#forwards>) you do not
help yourself understanding normal XSLT transformation if you run
stylesheet that way.

Transform">
<xsl:template match="/">

Inside a browser you usually want to transform XML to HTML so best
practice is to include the necessary elements making up a HTML document e.g.
<html>
<head>
<title>XSLT test</title>
</head>
<body>

<xsl:for-each select="Header">

The Header element is a child of the Data element so you need
<xsl:for-each select="Data/Header>

<xsl:value-of select="ID"></xsl:value-of>
</xsl:for-each>

</body>
</html>

</xsl:template>

--

Martin Honnen
http://JavaScript.FAQTs.com/

Mar 27 '07 #3

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