XSLT copying and enriching

[olivier.scalbert]

Hello,

How can I write the XSLT to transform:

<Root>
<Element attribute="value"/>
<Element2>
<Element3/>
</Element2>
</Root>

into:

<Root>
<Element attribute="value"/>
<Element2>
<Element3/>
</Element2>
<New element>
....
</New element>
</Root>

The output is the same as the input with a new element at the end.

Thanks for your help.
Olivier

[Martin Honnen]

ol**************@algosyn.com wrote:

How can I write the XSLT to transform:

<Root>
<Element attribute="value"/>
<Element2>
<Element3/>
</Element2>
</Root>

into:

<Root>
<Element attribute="value"/>
<Element2>
<Element3/>
</Element2>
<New element>
....
</New element>
</Root>

The output is the same as the input with a new element at the end.

Start with the identity transformation template
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
then add
<xsl:template match="Root">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
<New-Element>
....
</New-Element>
</xsl:copy>
</xsl:template>

--

Martin Honnen
http://JavaScript.FAQTs.com/

[olivier.scalbert]

Martin,

Thanks very much, it works !

Olivier

On Jan 26, 4:51 pm, Martin Honnen <[e-mail]:

Start with the identity transformation template
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
then add
<xsl:template match="Root">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
<New-Element>
....
</New-Element>
</xsl:copy>
</xsl:template>

--

Martin Honnen
http://JavaScript.FAQTs.com/