WebService Output Problem

[jlrodrigues]

I have this WebService with a webmethod tha returns XML, accessed by HTTP POST...

The webservice response is:

<?xml version="1.0" encoding="utf-8"?>
XML


For XML i create a XMLDocument into whom i load this string:

"<?xml-stylesheet type='text/xsl' href='http://localhost/myxslfile.xsl' ?><ReturnValue>answer from the WS</ReturnValue>"


my example XSL file (myxslfile.xsl) contents are:

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">
<xsl:template match="/">
<h3><xsl:value-of select="ReturnValue" /></h3>
</xsl:template>
</xsl:stylesheet>



Therefore, the Webservice response should be:

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type='text/xsl' href='http://localhost/myxslfile.xsl' ?><ReturnValue>answer from the WS</ReturnValue>


BUT IT KEEPS RETURNING ONLY

<?xml version="1.0" encoding="utf-8"?>
<ReturnValue>answer from the WS</ReturnValue>


Anyone knows what happened (obviously the Webservice took off the XSL reference), and how can i add that reference to the Output?

my method declaration is:

[WebMethod()]
public XmlDocument mymethod()
{
XmlDocument Retval = new XmlDocument();
string xml = "<?xml-stylesheet type='text/xsl' href='http://localhost/myxslfile.xsl' ?>"
+ "<ReturnValue>"
+ "answer from the WS" //Response String
+ "</ReturnValue>";
Retval.LoadXml(xml);
return Retval;
}



i even forced "<?xml version='1.0' ?><?xml-stylesheet type='text/xsl' href='http://www2.projectos.local/swsws/sws_sendsms.xsl' ?>" but it always keeps comming without those declarations.

Thanks in advance

[jlrodrigues]

Ok, folks, found it myself!

But, as it is a giant unanswered question, here goes the solution!

When returning a XMLDocument, the .NET removes any processing instruction from the XMLDocument, only gets the nodes!...

So, intead of returning a XMLDocument, let's play a trick to .NET!! Lets return a fragment of XML for it to append the main XML self-created Doxument. It goes like this


[WebMethod()]
public System.Xml.XmlDocumentFragment MyService()
{
XmlDocument _Xdoc = new XmlDocument();

XmlDocumentFragment Search = _Xdoc.CreateDocumentFragment();

string PItext = "type='text/xsl' href='****XSL FILE LOCATION****'";
XmlProcessingInstruction newPI = _Xdoc.CreateProcessingInstruction("xml-
stylesheet", PItext);
Search.AppendChild(newPI);

XmlNode _elem = _Xdoc.CreateNode(XmlNodeType.Element, "ReturnValue", "
http://www.domdigital.pt");
_elem.InnerText = "HELLO ANSWER!";
Search.AppendChild( _elem);

return Search;
}


Replace only ****XSL FILE LOCATION**** with your XSL file.


It solve my problem!

Cheers! Have a nice 2007!

[Coldfire]

i dont know about your problem..but hope that following book might help u

http://getonebyone.googlepages.com/ASP.NEtWebServices.zip

u can find more as per requrement from

http://getonebyone.googlepages.com/lectures
http://getonebyone.googlepages.com/home