Problem setting node-set in XsltArgumentList

[Sam]

I am working with .Net 2.0. I found a 2002 posting with this sample
code of how to send a node-set into a XSLT transformation:

string xml = @"<foo><bar>The Test</bar></foo>";
string xsl =
@"<xsl:stylesheet xmlns:xsl=""http://www.w3.org/1999/XSL/Transform""
version=""1.0"">
<xsl:param name=""param1""/>
<xsl:template match=""/"">
bar element from param1 value:
<xsl:copy-of select=""$param1/bar""/>
</xsl:template>
</xsl:stylesheet>";

XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
XPathNavigator nav = doc.CreateNavigator();

XslTransform xslt = new XslTransform();
xslt.Load(new XmlTextReader(new StringReader(xsl)));

XPathDocument dummy = new XPathDocument(new
StringReader("<dummy/>"));
XsltArgumentList args = new XsltArgumentList();
//Pass element foo as parameter
args.AddParam("param1", "", nav.Select("/foo"));
xslt.Transform(dummy, args, Console.Out);

The output I get is:

<?xml version="1.0" encoding="Windows-1252"?>
bar element from param1 value: <bar>The Test</bar>

If I am not mistaken, I should be getting:

<?xml version="1.0" encoding="Windows-1252"?>
bar element from param1 value: The Test

Does anyone know how to fix this sample to return the correct value?

Sam Carleton

[Martin Honnen]

Sam wrote:

I am working with .Net 2.0.

Note that the preferred .NET 2.0 XSLT processor is XslCompiledTransform
and not XslTransform.

string xml = @"<foo><bar>The Test</bar></foo>";

<xsl:copy-of select=""$param1/bar""/>

<?xml version="1.0" encoding="Windows-1252"?>
bar element from param1 value: <bar>The Test</bar>

If I am not mistaken, I should be getting:

<?xml version="1.0" encoding="Windows-1252"?>
bar element from param1 value: The Test

Why, xsl:copy-of copies the selected node, in this case the bar element,
to the result tree. So you end up with a copy of the complete element in
the result tree, that is the expected behaviour.
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/