xpath expression

[shapper]

Hello,

I am trying to use an XPath to select siteMapNode nodes where
footer=true.
What I have is:
siteMapNode[@footer='true']

It is not working.
My XML document is:

<?xml version="1.0" encoding="utf-8" ?>
<siteMap
xmlns = "http://schemas.microsoft.com/ASPNet/SiteMap-File-1.0" >
<siteMapNode>
<siteMapNode
url = "~/Default.aspx"
title = "Home"
description = "Desc1"
footer = "true" />
<siteMapNode
url = "~/Contacts.ASPx"
title = "Contactos"
description = "Desc2"
footer = "true" />
</siteMapNode>
</siteMap>

Could someone help me out?

Thanks,
Miguel

[Martin Honnen]

shapper wrote:

I am trying to use an XPath to select siteMapNode nodes where
footer=true.
What I have is:
siteMapNode[@footer='true']

<siteMap
xmlns = "http://schemas.microsoft.com/ASPNet/SiteMap-File-1.0" >

You have a default namespace declaration here meaning the elements are
in the namespace with URL
http://schemas.microsoft.com/ASPNet/SiteMap-File-1.0.

See <http://www.faqts.com/knowledge_base/view.phtml/aid/34022/fid/616>
for a solution.
--

Martin Honnen
http://JavaScript.FAQTs.com/

[Richard Tobin]

In article <11**********************@f16g2000cwb.googlegroups .com>,
shapper <md*****@gmail.comwrote:

>I am trying to use an XPath to select siteMapNode nodes where
footer=true.
What I have is:
siteMapNode[@footer='true']

><siteMap
xmlns = "http://schemas.microsoft.com/ASPNet/SiteMap-File-1.0" >
<siteMapNode>
<siteMapNode
url = "~/Default.aspx"
title = "Home"
description = "Desc1"
footer = "true" />

Your <siteMapNodeelements are in the

http://schemas.microsoft.com/ASPNet/SiteMap-File-1.0

namespace, so you have to do the same for your XPaths. XPath doesn't
use the default namespace so you'll have to declare a prefix and use
that, e.g.

sm:siteMapNode[@footer='true']

You haven't said what program you're using with these XPaths, so I
can't tell you how to declare the prefix. If it is in an XSLT
stylesheet, you can just declare it on the <xsl:stylesheetelement.
If you calling some XPath library, it will have a way to do it.

-- Richard

--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

[shapper]

Hello,

I am using VB.Net / Asp.Net to access my XML file.
The XPath is in my VB.Net code.

Thanks,
Miguel

Richard Tobin wrote:

In article <11**********************@f16g2000cwb.googlegroups .com>,
shapper <md*****@gmail.comwrote:

I am trying to use an XPath to select siteMapNode nodes where
footer=true.
What I have is:
siteMapNode[@footer='true']

<siteMap
xmlns = "http://schemas.microsoft.com/ASPNet/SiteMap-File-1.0" >
<siteMapNode>
<siteMapNode
url = "~/Default.aspx"
title = "Home"
description = "Desc1"
footer = "true" />

Your <siteMapNodeelements are in the

http://schemas.microsoft.com/ASPNet/SiteMap-File-1.0

namespace, so you have to do the same for your XPaths. XPath doesn't
use the default namespace so you'll have to declare a prefix and use
that, e.g.

sm:siteMapNode[@footer='true']

You haven't said what program you're using with these XPaths, so I
can't tell you how to declare the prefix. If it is in an XSLT
stylesheet, you can just declare it on the <xsl:stylesheetelement.
If you calling some XPath library, it will have a way to do it.

-- Richard

--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

[Joe Kesselman]

shapper wrote:

I am using VB.Net / Asp.Net to access my XML file.
The XPath is in my VB.Net code.

You'll have to look at the documentation for your XPath API to find out
how to tell it what the namespace bindings are. I don't go near VB or
..Net so I can't give you more specific advice.

XPaths are namespace-aware. You have to work with that.

--
() ASCII Ribbon Campaign | Joe Kesselman
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