Use
following-sibling::dd[preceding-sibling::dt[1]=current()]
get the following dd element whose first preceding dt is the surrent dt
element.
For instance the folllowing stylesheet
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<result>
<xsl:apply-templates select="//dt"/>
</result>
</xsl:template>
<xsl:template match="dt">
<for value="{.}">
<xsl:for-each
select="following-sibling::dd[preceding-sibling::dt[1]=current()]">
<got value="{.}"/>
</xsl:for-each>
</for>
</xsl:template>
</xsl:stylesheet>
will give you
<?xml version="1.0" encoding="utf-8"?>
<result>
<for value="A">
<got value="a"/>
</for>
<for value="B">
<got value="b1"/>
<got value="b2"/>
</for>
<for value="C"/>
<for value="D"/>
</result>
Note that the above assumes no namespace for the source elements, if
you use the XHTML namespace then you need to qualify the name tests
with the appropriate prefix, that is instead of dd for instance you
should have xhtml:dd and declare the XHTML namespace mapped to xhtml
prefix.
Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com 
