for example:
enum class SomeEnumType
{
A1 = 1;
A2 = 2;
A3 = 3;
};
how to write a function like:
bool isOneOfSomeEnumType(int i)? (in C++/CLI)
isOneOfSomeEnumType(1) will return true
isOneOfSomeEnumType(2) will return true
isOneOfSomeEnumType(4) will return false
somebody helps me! Thanks!
9  1924 
Hi Tau! for example:
enum class SomeEnumType
{
A1 = 1;
A2 = 2;
A3 = 3;
};
how to write a function like:
bool isOneOfSomeEnumType(int i)? (in C++/CLI)
return System::Enum::IsDefined(SomeEnumType::typeid, i);
--
Greetings
Jochen
My blog about Win32 and .NET http://blog.kalmbachnet.de/
> return System::Enum::IsDefined(SomeEnumType::typeid, i);
What exactly is 'typeid' here? Only thing I could find suggests I would need
an existing variable of SomeEnumType type to do a GetType() and get this
'typeid'. Put another way, does it takes one to know one? ; )
[==P==]
"Jochen Kalmbach [MVP]" <no********************@holzma.de> wrote in message
news:ux**************@TK2MSFTNGP10.phx.gbl... Hi Tau! for example:
enum class SomeEnumType
{
A1 = 1;
A2 = 2;
A3 = 3;
};
how to write a function like:
bool isOneOfSomeEnumType(int i)? (in C++/CLI)
return System::Enum::IsDefined(SomeEnumType::typeid, i);
--
Greetings
Jochen
My blog about Win32 and .NET
http://blog.kalmbachnet.de/
> Put another way, does it takes one to know one? ; ) I donīt understand...
Sorry, a bad attempt at humor. There is a saying "it takes one to know one".
In this context, if it was required to create an instance of an object type
in order to identify if another object is of the same type, I felt the
saying was somewhat appropriate and therefore kinda humerous. As you've
explained, however, this is not necessary, so the statement is not so funny
anymore....hehe
[==P==]
"Jochen Kalmbach [MVP]" <no********************@holzma.de> wrote in message
news:Oi*************@TK2MSFTNGP09.phx.gbl... Hi Peter!return System::Enum::IsDefined(SomeEnumType::typeid, i);
What exactly is 'typeid' here? Only thing I could find suggests I would
need an existing variable of SomeEnumType type to do a GetType() and get
this 'typeid'.
I C# the equivalent is "typeof(SomeEnumType)"...
See also:
http://msdn2.microsoft.com/en-us/library/ms235260.aspx
http://msdn2.microsoft.com/en-us/library/kwd9abya.aspx
For "typeid" you do not need to have a instance of the object....
Put another way, does it takes one to know one? ; )
I donīt understand...
--
Greetings
Jochen
My blog about Win32 and .NET
http://blog.kalmbachnet.de/
Hi Peter! Put another way, does it takes one to know one? ; )
I donÅ―t understand...
Sorry, a bad attempt at humor. There is a saying "it takes one to know one".
English is not my native language... so I didnÂīt know this term... but
now I learned thanks!
--
Greetings
Jochen
My blog about Win32 and .NET http://blog.kalmbachnet.de/
For someone who's 'english is not their native language' you communicate in
English a lot better than some people I know for whom 'english IS their
native language'... ; )
[==P==]
"Jochen Kalmbach [MVP]" <no********************@holzma.de> wrote in message
news:ux**************@TK2MSFTNGP09.phx.gbl... Hi Peter!Put another way, does it takes one to know one? ; )
I donZt understand...
Sorry, a bad attempt at humor. There is a saying "it takes one to know
one".
English is not my native language... so I didnīt know this term... but now
I learned thanks!
--
Greetings
Jochen
My blog about Win32 and .NET
http://blog.kalmbachnet.de/
"Peter Oliphant" wrote in message
news:%2****************@TK2MSFTNGP09.phx.gbl... Put another way, does it takes one to know one? ; )I donīt understand...
Sorry, a bad attempt at humor. There is a saying "it takes one to know
one".
The most common usage is in response to being called an idiot, newbie, or
other derogatory term. See also: "It takes a thief to catch a thief"
In this context, if it was required to create an instance of an object
type in order to identify if another object is of the same type, I felt
the saying was somewhat appropriate and therefore kinda humerous. As
you've explained, however, this is not necessary, so the statement is not
so funny anymore....hehe
[==P==]
"Jochen Kalmbach [MVP]" <no********************@holzma.de> wrote in
message news:Oi*************@TK2MSFTNGP09.phx.gbl... Hi Peter!return System::Enum::IsDefined(SomeEnumType::typeid, i);
What exactly is 'typeid' here? Only thing I could find suggests I would
need an existing variable of SomeEnumType type to do a GetType() and get
this 'typeid'.
I C# the equivalent is "typeof(SomeEnumType)"...
See also:
http://msdn2.microsoft.com/en-us/library/ms235260.aspx
http://msdn2.microsoft.com/en-us/library/kwd9abya.aspx
For "typeid" you do not need to have a instance of the object....
Put another way, does it takes one to know one? ; )
I donīt understand...
--
Greetings
Jochen
My blog about Win32 and .NET
http://blog.kalmbachnet.de/
Does this become a language learning thread?
I mean not the program language but the English language... :-)
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