Multiple web service classes in a single URL

[Howard Postley]

This seems like it's probably a pretty basic question but is there a way to
publish multiple classes from a single web service URL?

Using VS.NET, I create a project, FOO and add a web service, BAR, to it with
one function, baz(). Then, I create a second project to consume the service.
I add a web reference to http://webserver/FOO/BAR.asmx and call that,
BAR_Service. In the code, if I do something like:

dim ws as new BAR_Service.BAR
ws.baz()

My questions are:
Is there a way to add a second class to the web service that could be
referenced as, say, BAR_Service.BAR2? If not, why is the one and only class
that can be referenced by the web service not implicit in the reference to
the service?

Thanks for any help,

</hjp>

[NuTcAsE]

Yes you can add a second web service using the Add new item dialog in
VS. Say you a new web service named BOO with one function boo. After
doing so, update the web reference in your client project, your
BAR_Service will contain the following:

BAR_Service.BAR ws1 = new BAR_Service.BAR ()
ws1.baz();
BAR_Service.BOO ws2 = new BAR_Service.BOO ();
ws2.boo ();

Hope this helps...

- NuTcAsE

[Howard Postley]

That's what I thought should happen, as well. Alas... Each newly added web
service adds a new .asmx file. That .asmx file corresponds to an URL. Hence,
you have to add two references to the consuming app, one to
http://server/BAR.asmx (called BAR_Service) and a second one to
http://server/BOO.asmx (called BOO_Service) and then reference them:

BAR_Service.BAR ws1 = new BAR_Service.BAR()

and

BOO_Service.BOO ws2 = new BOO_Service.BOO()

I can find no way to add a single URL to the consuming app (called Service)
such that Service.BAR and Service.BOO are accessible.

"NuTcAsE" wrote:

Yes you can add a second web service using the Add new item dialog in
VS. Say you a new web service named BOO with one function boo. After
doing so, update the web reference in your client project, your
BAR_Service will contain the following:

BAR_Service.BAR ws1 = new BAR_Service.BAR ()
ws1.baz();
BAR_Service.BOO ws2 = new BAR_Service.BOO ();
ws2.boo ();

Hope this helps...

- NuTcAsE