validating XML against schema using JDOM

[srujana]

Hi

I am validating an xml document against schema .
when i am passing the xml file location as an input to the parse method

String XmlDocumentUrl="E:/books.xml";
parser.parse(XmlDocumentUrl);

it is working fine.

but how can i do that if i need to pass a xml document content instead
of the file location.

String XmlDocumentUrl="E:/books.xml";
InputSource inputSource = new InputSource(new
ByteArrayInputStream(XmlDocumentUrl.getBytes()));
parser.parse(inputSource);

The error is Cannot find the declaration of element 'Books'
'Books' is my root element.

Any help is greatly appreciated.
Thanks.

[Soren Kuula]

srujana wrote:

Hi

I am validating an xml document against schema .
when i am passing the xml file location as an input to the parse method

String XmlDocumentUrl="E:/books.xml";
parser.parse(XmlDocumentUrl);

it is working fine.

but how can i do that if i need to pass a xml document content instead
of the file location.

String XmlDocumentUrl="E:/books.xml";
InputSource inputSource = new InputSource(new
ByteArrayInputStream(XmlDocumentUrl.getBytes()));
parser.parse(inputSource);

The error is Cannot find the declaration of element 'Books'
'Books' is my root element.

It could be something with base URI?

With your first method, the parser has a chance to resolve relative URIs
in your document, in order to load other resources, such as the schema.
If the document contains this schema-location element thing (can't
remember its name) with schema location "foo.xsd", the parser will
resolve that to e:/foo.xsd . With your second method it doesn't have a
chance, because it never heard about e:/ .

You can probably set the base URI on the InputSource that you use,
letting the parser know the base URI. If you don't want to use
InputSources at all, you have to give the parser a schema location hint
by calling some method on it, or make your own entity resolver and have
to parser use that.

Soren

[Johannes Koch]

srujana wrote:

String XmlDocumentUrl="E:/books.xml";
InputSource inputSource = new InputSource(new
ByteArrayInputStream(XmlDocumentUrl.getBytes()));

This will create an input stream from the bytes in the string
"E:/books.xml", not from the bytes in the file referenced by "E:/books.xml".

--
Johannes Koch
Spem in alium nunquam habui praeter in te, Deus Israel.
(Thomas Tallis, 40-part motet)