Right, third time lucky, I'll try and explain this with some code examples:
The general theory here is build a dynamic aspx page, render the output to
an .aspx file that is then saved, this is the publised file. Imagine a Web
Content Management type
scenario.
pageA.aspx -
// generate the page output and save it to a output.aspx
// this is the published file that non admin users will see when browsing
the site
// A main reason for doing this is to save all the processing on each visit,
the users
// just see a published page, rather than a dynamically built one on each
visit.
protected override void Render(HtmlTextWriter writer)
{
StringBuilder sb = new StringBuilder();
StringWriter sw = new StringWriter(sb);
HtmlTextWriter htmlTR = new HtmlTextWriter(sw);
base.Render(htmlTR);
string filename = (string)Server.MapPath("readonly.aspx");
StreamWriter sr = new StreamWriter(filename, false, Encoding.UTF8);
sr.WriteLine(sb.ToString());
sr.Close();
}
output.aspx -
<html>
<head>
<title>output</title>
</head>
<body>
<form name="output" method="post" action="pageA.aspx?pageId=1"
id="output">
<input type="hidden" name="__VIEWSTATE"
value="dDw1MzgxO3Q8O2w8aTwxPjs+O2w8dDw7bDxpPDA+Oz4 7bDx0PDtsPGk8MT47PjtsPHQ8O2w
8aTwwPjs+O2w8dDw7bDxpPDA+Oz47bDx0PDtsPGk8MT47aTwzP jtpPDU+O2k8Nz47aTw5Pjs+>
<input name="Name" type="text" id="Name" />
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>
The problem is that because I'm saving the rendered pageA.aspx to a file
called output.aspx, the action/viewstate within the file is wrong.
If I then post a form on output.aspx it tries to post to pageA.aspx. I can
get around this and change the form action before I output the file to read:
<form name="output" method="post" action="output.aspx" id="output">
but this seems to result in viewstate not being restored to the form values.
Any ideas greatly appreciated.
Thanks
Kieran
1  1326 
Hi if you use
<form name="output" method="post" action="output.aspx" id="output"> for
posting to another
page ,you cant use server controls..Only normal html controls u can use.
"krs" wrote: Right, third time lucky, I'll try and explain this with some code examples:
The general theory here is build a dynamic aspx page, render the output to
an .aspx file that is then saved, this is the publised file. Imagine a Web
Content Management type
scenario.
pageA.aspx -
// generate the page output and save it to a output.aspx
// this is the published file that non admin users will see when browsing
the site
// A main reason for doing this is to save all the processing on each visit,
the users
// just see a published page, rather than a dynamically built one on each
visit.
protected override void Render(HtmlTextWriter writer)
{
StringBuilder sb = new StringBuilder();
StringWriter sw = new StringWriter(sb);
HtmlTextWriter htmlTR = new HtmlTextWriter(sw);
base.Render(htmlTR);
string filename = (string)Server.MapPath("readonly.aspx");
StreamWriter sr = new StreamWriter(filename, false, Encoding.UTF8);
sr.WriteLine(sb.ToString());
sr.Close();
}
output.aspx -
<html>
<head>
<title>output</title>
</head>
<body>
<form name="output" method="post" action="pageA.aspx?pageId=1"
id="output">
<input type="hidden" name="__VIEWSTATE"
value="dDw1MzgxO3Q8O2w8aTwxPjs+O2w8dDw7bDxpPDA+Oz4 7bDx0PDtsPGk8MT47PjtsPHQ8O2w
8aTwwPjs+O2w8dDw7bDxpPDA+Oz47bDx0PDtsPGk8MT47aTwzP jtpPDU+O2k8Nz47aTw5Pjs+>
<input name="Name" type="text" id="Name" />
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>
The problem is that because I'm saving the rendered pageA.aspx to a file
called output.aspx, the action/viewstate within the file is wrong.
If I then post a form on output.aspx it tries to post to pageA.aspx. I can
get around this and change the form action before I output the file to read:
<form name="output" method="post" action="output.aspx" id="output">
but this seems to result in viewstate not being restored to the form values.
Any ideas greatly appreciated.
Thanks
Kieran This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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