The assignment operator syntax shown previously:
MyClass% operator=(const MyClass%);
seems to have problems if you have member properties that need to be copied
from the rhs to the lhs. Since the rhs parameter is "const MyClass", you get
an error C2662 "'MyClass::prop::get' : cannot covert 'this' pointer from
'const MyClass' to 'MyClass %'" if you have code inside like
MyClass% MyClass::operator=(const MyClass %m)
{
....
prop = m.type
....
}
I can't make the get on the property return a const int. The compiler
doesn't like that either.
What's the correct syntax for an assignment operator and the copying of a
class's properties? The copy constructor doesn't have this problem since its
parameter isn't const.
-Rob
"Kapil Khosla [MSFT]" wrote:
"Rob" wrote:I'd like to know whether I should add copy and assignment constructors. The
standard syntax of
MyClass(const MyClass&);
MyClass& operator=(const MyClass&);
doesn't work. (compiler error C3699). Do I replace & with ^ ?
The equivalent code would be
ref class MyClass {
public:
MyClass(void);
~MyClass(void);
MyClass(MyClass%);
MyClass% operator=(const MyClass%);
};
Think of the operator equivalence for definitions like this:
& = %
* = ^
Dereferencing a ^ is still done with *, though.
