Find the depth of XML

[Raed Sawalha]

I have following XML:
How can I find the depth of XML?
in other word max level of the XML

<Root> ----- level 0
<Name>----- level 1
<FirstName>name</FirstName> ---- level 2
<LasName>lname</LastName>
<MiddleName>mName<MiddleName>
</Name>
<Information>
<Info1>
<Info2> --- level 3
<Info3>asdasd</Info> -- level 4
</Info2>
</Info1>

</Information>
</Root>

[Martin Honnen]

Raed Sawalha wrote:

I have following XML:
How can I find the depth of XML?
in other word max level of the XML

<Root> ----- level 0
<Name>----- level 1
<FirstName>name</FirstName> ---- level 2
<LasName>lname</LastName>
<MiddleName>mName<MiddleName>
</Name>
<Information>
<Info1>
<Info2> --- level 3
<Info3>asdasd</Info> -- level 4
</Info2>
</Info1>

</Information>
</Root>

XmlTextReader has a Depth property which you could store, however note
that with that approach the text node inside of the <Info3> element is
on level (or depth) 5:

XmlTextReader xmlReader = new XmlTextReader(@"test2005060501.xml");
int maxDepth = 0;
while (xmlReader.Read()) {
if (xmlReader.Depth > maxDepth) {
maxDepth = xmlReader.Depth;
}
Console.WriteLine(
"Node type: {0}, node name: {1}, node depth: {2}.", xmlReader.NodeType,
xmlReader.Name, xmlReader.Depth);
}
Console.Write("Maximum depth is: {0}.", maxDepth);

If you do not want to count text nodes or comment nodes you need to
check the NodeType and only change maxDepth for the node types you are
looking for.
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

[Dimitre Novatchev]

> How can I find the depth of XML?

in other word max level of the XML
Using XSLT 1.0 this can be done in the following way:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="//node()[not(node())]">
<xsl:sort select="count(ancestor::node())"
data-type="number" order="descending"/>

<xsl:if test="position()=1">
<xsl:value-of select="count(ancestor::node())"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Using XPath 2.0 one could write a single XPath expression which evaluates to
the maximum depth of the source xml document:

max(//*[not(*)]/count(ancestor::node()))

And the following XPath 2.0 expression selects all nodes that are at maximum
depth:
//*[not(*)][count(ancestor::node())
=
max(//*[not(*)]/count(ancestor::node()))
]

Cheers,
Dimitre Novatchev

"Raed Sawalha" <Ra*********@discussions.microsoft.com> wrote in message
news:04**********************************@microsof t.com...I have following XML:
How can I find the depth of XML?
in other word max level of the XML

<Root> ----- level 0
<Name>----- level 1
<FirstName>name</FirstName> ---- level 2
<LasName>lname</LastName>
<MiddleName>mName<MiddleName>
</Name>
<Information>
<Info1>
<Info2> --- level 3
<Info3>asdasd</Info> -- level 4
</Info2>
</Info1>

</Information>
</Root>