XSL Transform by DataType

[Deck]

Hello,

I am trying to find a way to format an XML attribute using XSL. I want to
run the format based on the datatype of the attribute.

I need to remove everything from the "-" in a attribute that is defined as a
datetime. I cannot go by the actual attribute name I need to process based
on data type. Any assistance would be greatly appreciated.

<s:Schema id="RowsetSchema">
<s:ElementType name="row" content="eltOnly" rs:updatable="true">
... more attributes just not showing them all...
<s:AttributeType name="BirthDate" rs:number="3">
<s:datatype dt:type="dateTime" dt:maxlength="-1"
rs:maybenull="True" />
</s:AttributeType>
</s:ElementType>
</s:Schema>
<rs:data>
<z:row BirthDate="1913-08-08T00:00:00.0000000-05:00" />
<z:row BirthDate="1920-08-08T00:00:00.0000000-06:00" />
<z:row BirthDate="1921-08-08T00:00:00.0000000-05:00" />
<z:row BirthDate="1925-08-08T00:00:00.0000000-06:00" />
<z:row BirthDate="1918-08-08T00:00:00.0000000-05:00" />
<z:row BirthDate="1935-08-08T00:00:00.0000000-06:00" />
</rs:data>

[Kevin Yu [MSFT]]

Hi Deck,

First of all, I would like to confirm my understanding of your issue. From
your description, I understand that you need to filter out all the dateTime
nodes in an Xml document. If there is any misunderstanding, please feel
free to let me know.

As far as I know, XSL cannot check a node for its type. Since all the
dateTime values are in certain format, you can try to use a regular
expression and search according to it.

HTH.

Kevin Yu
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