XslTransform.Transform fails when xsl contains node-set() Function

[John Sever]

My transform in cludes a variable that holds a node set from the node-set()
extension function. It the transformation works fine when using MSXML2 or
msxsl.exe but not in VB.Net.

My code looks something like this:

Dim XP as New XPathDocument(XMLFileName)
Dim XSLT as New XslTransform
XSLT.Load(XSLTFileName)
Dim Out as New MemoryStream
XSLT.Transform(XP.CreateNavigaotr, Nothing, Out, Nothing) <-- Fails on this
line
Out.Position = 0
Dim XML as New XmlDocument
XML.LoadXml(New StreamReader(Out).ReadToEnd)

The exception says:
System.Xml.Xsl.XsltException: Function 'msxsl:node-set()' has failed. --->
System.Xml.Xsl.XsltException: Cannot convert the operand to 'Result tree
fragment'.

I've spent days trying to figure it out with no luck. Any suggestions?

[Martin Honnen]

John Sever wrote:

My transform in cludes a variable that holds a node set from the node-set()
extension function. It the transformation works fine when using MSXML2 or
msxsl.exe but not in VB.Net.

My code looks something like this:

Dim XP as New XPathDocument(XMLFileName)
Dim XSLT as New XslTransform
XSLT.Load(XSLTFileName)
Dim Out as New MemoryStream
XSLT.Transform(XP.CreateNavigaotr, Nothing, Out, Nothing) <-- Fails on this
line
Out.Position = 0
Dim XML as New XmlDocument
XML.LoadXml(New StreamReader(Out).ReadToEnd)

The exception says:
System.Xml.Xsl.XsltException: Function 'msxsl:node-set()' has failed. --->
System.Xml.Xsl.XsltException: Cannot convert the operand to 'Result tree
fragment'.

I've spent days trying to figure it out with no luck. Any suggestions?

I don't think that .NET supports the node-set function.
--

Martin Honnen
http://JavaScript.FAQTs.com/

[Dimitre Novatchev [MVP XML]]

And where is your XSLT code?
"John Sever" <jo*******@cascon.com> wrote in message
news:uk**************@TK2MSFTNGP10.phx.gbl...

My transform in cludes a variable that holds a node set from the node-set() extension function. It the transformation works fine when using MSXML2 or
msxsl.exe but not in VB.Net.

My code looks something like this:

Dim XP as New XPathDocument(XMLFileName)
Dim XSLT as New XslTransform
XSLT.Load(XSLTFileName)
Dim Out as New MemoryStream
XSLT.Transform(XP.CreateNavigaotr, Nothing, Out, Nothing) <-- Fails on this line
Out.Position = 0
Dim XML as New XmlDocument
XML.LoadXml(New StreamReader(Out).ReadToEnd)

The exception says:
System.Xml.Xsl.XsltException: Function 'msxsl:node-set()' has failed. --->
System.Xml.Xsl.XsltException: Cannot convert the operand to 'Result tree
fragment'.

I've spent days trying to figure it out with no luck. Any suggestions?

[Dimitre Novatchev [MVP XML]]

"Dimitre Novatchev [MVP XML]" <dn********@yahoo.com> wrote in message
news:c4*************@ID-152440.news.uni-berlin.de...

And where is your XSLT code?
By asking this I wanted to say that I have many examples of code, containing
the xxx:node-set() extension function, that works OK with the .Net Framework
1.1

Also, Msxml2 didn't implement XSLT -- it did implement an obsolete WD
dialect, which is no longer supported in either MSXML4 or .Net XslTransform.

Actually, what the error message says is quite clear -- you haven't provided
an RTF as argument to msxsl:node-set(), but something else -- e.g a string
or a number.

Show us your code and anyone will be able to point out the exact cause of
this error.
Cheers,

Dimitre Novatchev [XML MVP],
FXSL developer, XML Insider,

http://fxsl.sourceforge.net/ -- the home of FXSL
Resume: http://fxsl.sf.net/DNovatchev/Resume/Res.html



"John Sever" <jo*******@cascon.com> wrote in message
news:uk**************@TK2MSFTNGP10.phx.gbl...

My transform in cludes a variable that holds a node set from the

node-set()

extension function. It the transformation works fine when using MSXML2 or msxsl.exe but not in VB.Net.

My code looks something like this:

Dim XP as New XPathDocument(XMLFileName)
Dim XSLT as New XslTransform
XSLT.Load(XSLTFileName)
Dim Out as New MemoryStream
XSLT.Transform(XP.CreateNavigaotr, Nothing, Out, Nothing) <-- Fails on

this

line
Out.Position = 0
Dim XML as New XmlDocument
XML.LoadXml(New StreamReader(Out).ReadToEnd)

The exception says:
System.Xml.Xsl.XsltException: Function 'msxsl:node-set()' has failed. ---> System.Xml.Xsl.XsltException: Cannot convert the operand to 'Result tree
fragment'.

I've spent days trying to figure it out with no luck. Any suggestions?

[NaraendiraKumar R. R.]

I've have been able to use msxsl:the node-set() function successfully in
..NET 1.0 & .NET 1.1.

Could you share the XSLT &/or XML with us?

----
"Martin Honnen" <ma*******@yahoo.de> wrote in message
news:Oz**************@TK2MSFTNGP12.phx.gbl...

John Sever wrote:

My transform in cludes a variable that holds a node set from the node-set() extension function. It the transformation works fine when using MSXML2 or msxsl.exe but not in VB.Net.

My code looks something like this:

Dim XP as New XPathDocument(XMLFileName)
Dim XSLT as New XslTransform
XSLT.Load(XSLTFileName)
Dim Out as New MemoryStream
XSLT.Transform(XP.CreateNavigaotr, Nothing, Out, Nothing) <-- Fails on this line
Out.Position = 0
Dim XML as New XmlDocument
XML.LoadXml(New StreamReader(Out).ReadToEnd)

The exception says:
System.Xml.Xsl.XsltException: Function 'msxsl:node-set()' has failed. ---> System.Xml.Xsl.XsltException: Cannot convert the operand to 'Result tree
fragment'.

I've spent days trying to figure it out with no luck. Any suggestions?

I don't think that .NET supports the node-set function.
--

Martin Honnen
http://JavaScript.FAQTs.com/

[Kevin Yu [MSFT]]

Hi John,

I'd like to know if this issue has been resolved yet. Is there anything
that I can help. I'm still monitoring on it. If you have any questions,
please feel free to post them in the community.

Kevin Yu
=======
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