XSLT Extension Object Problem

[Matt Frame]

In my old VB6 application I have an xslt extension object that builds a
small cross reference document and returns it as a NodeList in my XSLT. I
can then use it with xpath expressions as $nodeset/xpath and I would get my
values or use xsl:copy-of and I would get the whole document in my results
tree. In my .Net version I don't get anything with my $nodeset/xpath
expression and if I use the xsl:copy-of I get a value of
System.Xml.XPath.XPathNodeList. I know this is the real object of the
node set but what am I doing wrong for it not to be a node-set when it
returns to my XSLT? Anyone have any ideas? I even tried wrapping the
result with msxsl:node-set() and I received all kinds of error from my XSLT
processor then.

Thanks,

Matt

[Oleg Tkachenko [MVP]]

Matt Frame wrote:

In my old VB6 application I have an xslt extension object that builds a
small cross reference document and returns it as a NodeList in my XSLT. I
can then use it with xpath expressions as $nodeset/xpath and I would get my
values or use xsl:copy-of and I would get the whole document in my results
tree. In my .Net version I don't get anything with my $nodeset/xpath
expression and if I use the xsl:copy-of I get a value of
System.Xml.XPath.XPathNodeList.

What do you return from the extension object? It must be
XPathNodeIterator to be passed as nodeset or XPathNavigator as result
tree fragment.

--
Oleg Tkachenko [XML MVP, XmlInsider]
http://blog.tkachenko.com

[Matt Frame]

Oleg,

Once again you are FANTASTIC!

Thanks for the help.

Matt
"Oleg Tkachenko [MVP]" <oleg@NO!SPAM!PLEASEtkachenko.com> wrote in message
news:%2******************@TK2MSFTNGP10.phx.gbl...

Matt Frame wrote:

In my old VB6 application I have an xslt extension object that builds a
small cross reference document and returns it as a NodeList in my XSLT. I can then use it with xpath expressions as $nodeset/xpath and I would get my values or use xsl:copy-of and I would get the whole document in my results tree. In my .Net version I don't get anything with my $nodeset/xpath
expression and if I use the xsl:copy-of I get a value of
System.Xml.XPath.XPathNodeList.

What do you return from the extension object? It must be
XPathNodeIterator to be passed as nodeset or XPathNavigator as result
tree fragment.

--
Oleg Tkachenko [XML MVP, XmlInsider]
http://blog.tkachenko.com