Problems with mixed content type.

[Anas M. Nebuchadnezzar XXXVII]

I have an Xml file that I am trying to transform using an Xsl
stylesheet. My data is in the form of:

<root>
...
<aaa>
<bbb>Mixed content type, with <def link="words">words</def>
defined in between pure text</bbb>
</aaa>
...
</root>

and the stylesheet I've been using looks something like:

<xsl:template match="aaa/bbb">
<xsl:apply-templates select="./*" />
</xsl:template>

<xsl:template match="def[@link]">
<xsl:element name="a">
<xsl:attribute name="href">
display.aspx?name=<xsl:value-of select="@link" />
</xsl:attribute>
<xsl:value-of select="." />
</xsl:element>
</xsl:template>

<xsl:template match="text()">
<xsl:value-of select="." />
</xsl:template>

And what I want is to get something along the lines of:
Mixed content type, with <a
href="display.aspx?name=words">words</def> defined in between pure text

I've tried several different way, managed to get eaither the text, or
the links, or both seperatly, but not both at the same time.

A previous post mentioned using <xsl:copy-of>, but I didn't understand
how that would help. Any ideas would be greatly apreciated.

[Oleg Tkachenko]

Anas M. Nebuchadnezzar XXXVII wrote:

I have an Xml file that I am trying to transform using an Xsl
stylesheet. My data is in the form of:

<root>
...
<aaa>
<bbb>Mixed content type, with <def link="words">words</def>
defined in between pure text</bbb>
</aaa>
...
</root>

and the stylesheet I've been using looks something like:

<xsl:template match="aaa/bbb">
<xsl:apply-templates select="./*" /> Here you are applying templates only to children elements, leaving text
nodex out. Try instead <xsl:apply-templates/>
<xsl:template match="text()">
<xsl:value-of select="." />
</xsl:template>

This template could be omitted, because it duplicates built-in one.
--
Oleg Tkachenko
XmlInsider
http://blog.tkachenko.com