Condition-clause in XSLT using .Net System.Xml

[Magus]

Hi.

I'm trying to execute a simple <xsl:if>-clause with a
condition that reads: a<1
In MSXML 4 the clause <xsl:if test="a &lt; 1">do
something...</xsl:if> works fine.
But in .Net Xml it just doesn't work. I can't use the real
character (<) because the XSLT wont be a valid XML.
And if I use the encoded representation (&lt;) it wont
compute at all.

Anybody got a clue what to do???

// Magus - Il Dottore

[Oleg Tkachenko]

Magus wrote:

I'm trying to execute a simple <xsl:if>-clause with a
condition that reads: a<1
In MSXML 4 the clause <xsl:if test="a &lt; 1">do
something...</xsl:if> works fine.
But in .Net Xml it just doesn't work. I can't use the real
character (<) because the XSLT wont be a valid XML.
And if I use the encoded representation (&lt;) it wont
compute at all.

Sounds weird. &lt; is exactly the same as < and of course works. Show us
reporoducible sample.
--
Oleg Tkachenko
http://www.tkachenko.com/blog
Multiconn Technologies, Israel

[Magus]

It is weird.
Just make a simple XSLT file containíng.

<xsl:template match="root">
<root>
<xsl:if test="@a &lt; 5">
<element />
</xsl:if>
</root>
</xsl:template>

then write some simple C# code and use the System.Xml
assembly to transform the simple XML-document
<root a="4" />

the result should be <root><element /></root>

What result do you get?

/Magus

-----Original Message-----
Magus wrote:

I'm trying to execute a simple <xsl:if>-clause with a
condition that reads: a<1
In MSXML 4 the clause <xsl:if test="a < 1">do
something...</xsl:if> works fine.
But in .Net Xml it just doesn't work. I can't use the real character (<) because the XSLT wont be a valid XML.
And if I use the encoded representation (<) it wont
compute at all.
Sounds weird. < is exactly the same as < and of course

works. Show us reporoducible sample.
--
Oleg Tkachenko
http://www.tkachenko.com/blog
Multiconn Technologies, Israel

.

[M]

Try using
1>a
....instead.

///M

"Magus" <il**************@hotmail.con> wrote in message
news:04****************************@phx.gbl...

Hi.

I'm trying to execute a simple <xsl:if>-clause with a
condition that reads: a<1
In MSXML 4 the clause <xsl:if test="a &lt; 1">do
something...</xsl:if> works fine.
But in .Net Xml it just doesn't work. I can't use the real
character (<) because the XSLT wont be a valid XML.
And if I use the encoded representation (&lt;) it wont
compute at all.

Anybody got a clue what to do???

// Magus - Il Dottore

[Magus]

Problem solved.
I applied the latest SP and voila.
There was something wrong with my installation.

Thanx anyways for your attention.

/Magus

-----Original Message-----
It is weird.
Just make a simple XSLT file containíng.

<xsl:template match="root">
<root>
<xsl:if test="@a < 5">
<element />
</xsl:if>
</root>
</xsl:template>

then write some simple C# code and use the System.Xml
assembly to transform the simple XML-document
<root a="4" />

the result should be <root><element /></root>

What result do you get?

/Magus

-----Original Message-----
Magus wrote:

I'm trying to execute a simple <xsl:if>-clause with a
condition that reads: a<1
In MSXML 4 the clause <xsl:if test="a < 1">do
something...</xsl:if> works fine.
But in .Net Xml it just doesn't work. I can't use the real character (<) because the XSLT wont be a valid XML.
And if I use the encoded representation (<) it wont
compute at all.

Sounds weird. < is exactly the same as < and of course

works. Show us

reporoducible sample.
--
Oleg Tkachenko
http://www.tkachenko.com/blog
Multiconn Technologies, Israel

.

.