Read XML

[Paul Marrero]

I'm sure this has been asked before, but with over 3,000 listings...Anyway,
what I want to do is load an XML file so I can populate the text property of
a label in VB .NET.

The XML file is as follows:

<orglevels>
<code>2</code>
<desc>Tampa Division</desc>
</orglevels>
<orglevels>
<code>3</code>
<desc>Software Development</desc>
</orglevels>

I want to read this XML file and display the description ("Desc") so that
it diplays on a Windows Form.
For example: label.text = orglevels.desc

TIA.
-Paul

[Oleg Tkachenko]

Paul Marrero wrote:

I'm sure this has been asked before, but with over 3,000 listings...Anyway,
what I want to do is load an XML file so I can populate the text property of
a label in VB .NET.

The XML file is as follows:

<orglevels>
<code>2</code>
<desc>Tampa Division</desc>
</orglevels>
<orglevels>
<code>3</code>
<desc>Software Development</desc>
</orglevels>

I want to read this XML file and display the description ("Desc") so that
it diplays on a Windows Form.
For example: label.text = orglevels.desc

I think XmlSerializer can fit your needs in the most elegant way:

XML doc:
<Organization xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<orglevels>
<code>2</code>
<desc>Tampa Division</desc>
</orglevels>
<orglevels>
<code>3</code>
<desc>Software Development</desc>
</orglevels>
</Organization>

Plumbing:

namespace Test2 {

public class Organization {
[XmlElement("orglevels")]
public OrgLevel[] orglevels;
public class OrgLevel {
public int code;
public string desc;
}
}

public class Test {
static void Main(string[] args) {
XmlSerializer serializer = new XmlSerializer(typeof(Organization));
//Deserialize organization description
Organization org = (Organization)serializer.Deserialize(new
StreamReader("org.xml"));
foreach (Organization.OrgLevel orglevel in org.orglevels)
Console.WriteLine("orglevel code: {0}, desc: {1}",
orglevel.code, orglevel.desc);
}
}
}

--
Oleg Tkachenko
http://www.tkachenko.com/blog
Multiconn Technologies, Israel

[vector]

Oleg Tkachenko <oleg@NO_SPAM_PLEASEtkachenko.com> wrote in message news:<#v**************@TK2MSFTNGP11.phx.gbl>...

I think XmlSerializer can fit your needs in the most elegant way:

XML doc:
<Organization xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<orglevels>
<code>2</code>
<desc>Tampa Division</desc>
</orglevels>
<orglevels>
<code>3</code>
<desc>Software Development</desc>
</orglevels>
</Organization>

Plumbing:

namespace Test2 {

public class Organization {
[XmlElement("orglevels")]
public OrgLevel[] orglevels;
public class OrgLevel {
public int code;
public string desc;
}
}

public class Test {
static void Main(string[] args) {
XmlSerializer serializer = new XmlSerializer(typeof(Organization));
//Deserialize organization description
Organization org = (Organization)serializer.Deserialize(new
StreamReader("org.xml"));
foreach (Organization.OrgLevel orglevel in org.orglevels)
Console.WriteLine("orglevel code: {0}, desc: {1}",
orglevel.code, orglevel.desc);
}
}
}

Can XmlSerialization be used in conjunction with some technique to
produce a schema alongside the OrgLevel elements? For example:

<root>
<xs:schema elementFormDefault="qualified"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="OrgLevel">
<xs:complexType>
<xs:sequence>
<xs:element name="code" type="integer" />
<xs:element name="desc" type="string" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>

<OrgLevel>
<code>2</code>
<desc>Tampa Division</desc>
</OrgLevel>

<OrgLevel>
<code>3</code>
<desc>Software Development</desc>
</OrgLevel>

</root>