position() in XPath has wrong reference

[Matthias Lohrer]

Hi,

my XML-Document hat this structure
<book>
<section>
<para />
<para />
</section>
<section>
<para />
<para />
</section>
</book>...

Now I need to find the third para-element of all para-Elements.
In my XSLT-Stylesheet I write

<xsl:template match="para">
<xsl:if test="position()= 3" >
do something
</xsl:if>
</xsl:template>

This does not work. He finds nothing. When I test
position()=1
he finds the first para of the first section and the first para of the
second section

Is there any possibility to find out the position of the current para-node
comparing to _all_ para-elements within the whole document?

Thanks

Matthias
[e-mail]

[Matthias Lohrer]

Hi,

what you say is right, but it doesn't answer my question:

when I use
<xsl:template match="//section/para"> ...

it is the same:
<xsl:if test="position()= 3" > will have no result
and <xsl:if test="position()= 1" > has 2 results

when I use
<xsl:template match="//para">
<xsl:if test="position()= 1" >
I get 2 results

when I use
<xsl:template match="//para">
<xsl:if test="position()= 3" >
I get 0 results.

So the logic is always the same:
The context is made up by the para-Element with the same
parent-section-Element.

I seems not to be possible to create a context that consists only of
all para-Elements without respect of the parent-section-element, and this
is, what I'm looking for.

Matthias
"Yuriy Solodkyy" <[e-mail]> schrieb im Newsbeitrag
news:Oo**************@TK2MSFTNGP10.phx.gbl...

Hi,
See the "position Function" reference in "Microsoft XML Core Services
(MSXML) 4.0 - XPath Reference". The position() function is sensetive to the calling context. For exaple, if you apply-templates to select "//para" you will have different result, or even if select is section/para than if you
apply templates separately for each section or default templates are used.

The sample SDK describes this in details.

Yuriy

"Matthias Lohrer" <ma*************@mlohrer.de> wrote in message
news:3f*********************@read.news.de.uu.net.. .

Hi,

my XML-Document hat this structure
<book>
<section>
<para />
<para />
</section>
<section>
<para />
<para />
</section>
</book>...

Now I need to find the third para-element of all para-Elements.
In my XSLT-Stylesheet I write

<xsl:template match="para">
<xsl:if test="position()= 3" >
do something
</xsl:if>
</xsl:template>

This does not work. He finds nothing. When I test
position()=1
he finds the first para of the first section and the first para of the
second section

Is there any possibility to find out the position of the current para-node comparing to _all_ para-elements within the whole document?

Thanks

Matthias
[e-mail]

[Yuriy Solodkyy]

The following sample returns one element, see:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

<xsl:output method="xml" indent="yes" encoding="utf-8"/>

<xsl:template match="/">
<r>
<xsl:apply-templates select="//para" />
</r>
</xsl:template>

<xsl:template match="para">
<xsl:if test="position() = 3">
<yes />
</xsl:if>
</xsl:template>

</xsl:stylesheet>

"Matthias Lohrer" <ma*************@mlohrer.de> wrote in message
news:3f*********************@read.news.de.uu.net.. . Hi,

what you say is right, but it doesn't answer my question:

when I use
<xsl:template match="//section/para"> ...

it is the same:
<xsl:if test="position()= 3" > will have no result
and <xsl:if test="position()= 1" > has 2 results

when I use
<xsl:template match="//para">
<xsl:if test="position()= 1" >
I get 2 results

when I use
<xsl:template match="//para">
<xsl:if test="position()= 3" >
I get 0 results.

So the logic is always the same:
The context is made up by the para-Element with the same
parent-section-Element.

I seems not to be possible to create a context that consists only of
all para-Elements without respect of the parent-section-element, and this
is, what I'm looking for.

Matthias
"Yuriy Solodkyy" <[e-mail]> schrieb im Newsbeitrag
news:Oo**************@TK2MSFTNGP10.phx.gbl...

Hi,
See the "position Function" reference in "Microsoft XML Core Services
(MSXML) 4.0 - XPath Reference". The position() function is sensetive to

the

calling context. For exaple, if you apply-templates to select "//para"

you

will have different result, or even if select is section/para than if you

apply templates separately for each section or default templates are used.
The sample SDK describes this in details.

Yuriy

"Matthias Lohrer" <ma*************@mlohrer.de> wrote in message
news:3f*********************@read.news.de.uu.net.. .

Hi,

my XML-Document hat this structure
<book>
<section>
<para />
<para />
</section>
<section>
<para />
<para />
</section>
</book>...

Now I need to find the third para-element of all para-Elements.
In my XSLT-Stylesheet I write

<xsl:template match="para">
<xsl:if test="position()= 3" >
do something
</xsl:if>
</xsl:template>

This does not work. He finds nothing. When I test
position()=1
he finds the first para of the first section and the first para of the
second section

Is there any possibility to find out the position of the current

para-node comparing to _all_ para-elements within the whole document?

Thanks

Matthias
[e-mail]

[Matthias Lohrer]

Indeed, now it works.
I see the difference: You created a new context by using
<xsl:apply-templates select="//para"> instead of modifying the
match-attribute of the template. We in germany say "Gewusst wie!"
Thank you!

"Yuriy Solodkyy" <[e-mail]> schrieb im Newsbeitrag
news:uR**************@TK2MSFTNGP12.phx.gbl...

The following sample returns one element, see:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

<xsl:output method="xml" indent="yes" encoding="utf-8"/>

<xsl:template match="/">
<r>
<xsl:apply-templates select="//para" />
</r>
</xsl:template>

<xsl:template match="para">
<xsl:if test="position() = 3">
<yes />
</xsl:if>
</xsl:template>

</xsl:stylesheet>

"Matthias Lohrer" <ma*************@mlohrer.de> wrote in message
news:3f*********************@read.news.de.uu.net.. .