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Xsl position()

Hi I hava a xsl question.
How do I get the position of the parent a in the in the template for
b?

Example:

<root>
<a>
<b></b>
</a>
<a>
<b></b>
</a>
</root>

<xsl:template match="/root">
<xsl:apply-templates select="a"/>
</xsl:template>

<xsl:template match="a">
<xsl:apply-templates select="b"/>
</xsl:template>

<xsl:template match="b">
<xsl:value-of select="../position()"/>
</xsl:template>
Nov 11 '05 #1
1 6053
Hugo Wetterberg wrote:
How do I get the position of the parent a in the in the template for
b?

Example:

<root>
<a>
<b></b>
</a>
<a>
<b></b>
</a>
</root>

<xsl:template match="/root">
<xsl:apply-templates select="a"/>
</xsl:template>

<xsl:template match="a">
<xsl:apply-templates select="b"/>
</xsl:template>

<xsl:template match="b">
<xsl:value-of select="../position()"/>


<xsl:value-of select="count(../preceding-sibling::*)+1"/>

--
Oleg Tkachenko
http://www.tkachenko.com/blog
Multiconn Technologies, Israel

Nov 11 '05 #2

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