XSLT problem

[Tech]

Hello,

I want to transfer a XML node with a XSL stylesheet into another XML
document like this:

source XML...
---------------------------
....
<flowText font-size="20" xml:space="preserve"
xmlns="http://xml.apache.org/batik/ext">
Hello World
</flowText>
....

xsl...
---------------------------
....
<xsl:template match="flowText ">
Test...
<xsl:apply-templates/>
</xsl:template>
....

result XML (I want to see this...)
----------------------------
Test... Hello World
(but I see nothing)
-----------------------------
I think the processor can´t find the node because of this
"xml:space="preserve" xmlns="http://xml.apache.org/batik/ext"
attribute! Did anybody know a solution of my problem?

THX

[Martin Honnen]

Tech wrote:

I want to transfer a XML node with a XSL stylesheet into another XML
document like this:

source XML...
---------------------------
...
<flowText font-size="20" xml:space="preserve"
xmlns="http://xml.apache.org/batik/ext">
Hello World
</flowText>
...

xsl...
You need
<xsl:stylesheet
xmlns:somePrefix="http://xml.apache.org/batik/ext" ...> ...
<xsl:template match="flowText ">
<xsl:template match="somePrefix:flowText">
Test...
<xsl:apply-templates/>
</xsl:template>
...

--

Martin Honnen
http://JavaScript.FAQTs.com/

[Patrick TJ McPhee]

In article <de**************************@posting.google.com >,
Tech <so***@gmx.de> wrote:

[...]

% result XML (I want to see this...)
% ----------------------------
% Test... Hello World

In addition to the name-space issue mentioned in another reply, this is
not XML. You'll need <xsl:output method='text'/> at the top of the style
sheet to get this output.

--

Patrick TJ McPhee
East York Canada
pt**@interlog.com