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strtok

Hello,
some function which could parse string into tokens the same way the C
function "strtok" does?

Ondra.

Jul 21 '05 #1
2 2868
Ondra,
Have you looked at the Split function?

There are three Split functions in VB.NET:

Use Microsoft.VisualBasic.Strings.Split if you need to split a string based
on a specific word (string). It is the Split function from VB6.

Use System.String.Split if you need to split a string based on a collection
of specific characters. Each individual character is its own delimiter.

Alternatively use System.Text.RegularExpressions.RegEx.Split to split based
on matching patterns.

If you are using C#, you can reference the Microsoft.VisualBasic.dll
assembly to use the first function.

Hope this helps
Jay

"Ondrej Sevecek" <on***@sevecek.com.thisisanuntispamsuffix> wrote in message
news:ux**************@TK2MSFTNGP11.phx.gbl...
Hello,
some function which could parse string into tokens the same way the C
function "strtok" does?

Ondra.

Jul 21 '05 #2
many thanks.
"Jay B. Harlow [MVP - Outlook]" <Ja********@email.msn.com> wrote in message
news:OQ**************@TK2MSFTNGP11.phx.gbl...
Ondra,
Have you looked at the Split function?

There are three Split functions in VB.NET:

Use Microsoft.VisualBasic.Strings.Split if you need to split a string based on a specific word (string). It is the Split function from VB6.

Use System.String.Split if you need to split a string based on a collection of specific characters. Each individual character is its own delimiter.

Alternatively use System.Text.RegularExpressions.RegEx.Split to split based on matching patterns.

If you are using C#, you can reference the Microsoft.VisualBasic.dll
assembly to use the first function.

Hope this helps
Jay

"Ondrej Sevecek" <on***@sevecek.com.thisisanuntispamsuffix> wrote in message news:ux**************@TK2MSFTNGP11.phx.gbl...
Hello,
some function which could parse string into tokens the same way the C
function "strtok" does?

Ondra.


Jul 21 '05 #3

This thread has been closed and replies have been disabled. Please start a new discussion.

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