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How can i put all tag contents into CDATA?

How can i put all tag contents into <![CDATA[...]]> (i mean using XSL)

For example. I have

<firstname>John </firstname>
<lastname>Malko vich</lastname>

And i want to get:
<firstname>Alex ey</firstname>
<lastname>Alexe ev</lastname>
Jul 20 '05 #1
2 2456
One must avoid to do this, if possible.


Dimitre Novatchev [XML MVP],
FXSL developer, XML Insider,

http://fxsl.sourceforge.net/ -- the home of FXSL
Resume: http://fxsl.sf.net/DNovatchev/Resume/Res.html

"DZ" <al************ *@hotmail.com> wrote in message
news:aa******** *************** ***@posting.goo gle.com...
How can i put all tag contents into <![CDATA[...]]> (i mean using XSL)

For example. I have

<firstname>John </firstname>
<lastname>Malko vich</lastname>

And i want to get:
<firstname>Alex ey</firstname>
<lastname>Alexe ev</lastname>

Jul 20 '05 #2
In article <aa************ **************@ posting.google. com>,
DZ <al************ *@hotmail.com> wrote:
% How can i put all tag contents into <![CDATA[...]]> (i mean using XSL)
% For example. I have
% ...
% <name>
% <firstname>John </firstname>
% <lastname>Malko vich</lastname>
% <name>
% ....
% And i want to get:
% <name><![CDATA[
% <firstname>Alex ey</firstname>
% <lastname>Alexe ev</lastname>
% ]]></name>

You can't do this with XSL. What you've written is exactly the same as

&lt;firstname>A lexey&lt;/firstname>
&lt;lastname>Al exeev&lt;/lastname>

and the XSLT processor is free to pick its quoting method, which will
always be to use &lt; because apart from me nobody seems to like CDATA
sections much.

Actually, I suppose you could do it by building it (including the <!CDATA[[
and ]]>) in an xsl:text element and disabling output escaping, then
serialising the result tree. I'll leave that as an exercise.

Patrick TJ McPhee
East York Canada
pt**@interlog.c om
Jul 20 '05 #3

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