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Is integer division always truncated

In .NET, can I be sure that the result of a division between two integers
always is truncated rather that rounded to nearest?

Example:
99 / 50 = 1

regards, Teis
Jul 21 '05 #1
24 19326
Yes. You can also get the remainder that results in an integer division.

If you need rounding, use floating point division and round the result.

"Teis Draiby" <te************ *@draiby.com> wrote in message
news:u8******** ******@TK2MSFTN GP11.phx.gbl...
In .NET, can I be sure that the result of a division between two integers
always is truncated rather that rounded to nearest?

Example:
99 / 50 = 1

regards, Teis

Jul 21 '05 #2
Ah! That must be the Math.IEEERemain der()

Thanks, Teis
Jul 21 '05 #3
I don't think so. At first I would have said "yes" agreed with you. But in machine language .99999999999999 99 is 1
not 0 16 bit here. In other words in pure mathematics .99999... = 1 but the machine cannot run out to infinity it can only
run out to the bits allowed allowed for integers. In this case ..99999....9 = 1. We'd have to test that to be sure but that
seems reasonable.

--
George Hester
_______________ _______________ ___
"Marina" <so*****@nospam .com> wrote in message news:eT******** ******@tk2msftn gp13.phx.gbl...
Yes. You can also get the remainder that results in an integer division.

If you need rounding, use floating point division and round the result.

"Teis Draiby" <te************ *@draiby.com> wrote in message
news:u8******** ******@TK2MSFTN GP11.phx.gbl...
In .NET, can I be sure that the result of a division between two integers
always is truncated rather that rounded to nearest?

Example:
99 / 50 = 1

regards, Teis





Jul 21 '05 #4

"Teis Draiby" <te************ *@draiby.com> wrote in message
news:u8******** ******@TK2MSFTN GP11.phx.gbl...
In .NET, can I be sure that the result of a division between two integers
always is truncated rather that rounded to nearest?

Example:
99 / 50 = 1

regards, Teis


Um, I would have to disagree with those that say yes.
I haven't taken it to the IL or assembly level, but I believe as written the
values will be cast to doubles, divided, then the result rounded to get your
Integer. Even if that is not exactly what happens, you will NOT get 1.

The key here is the operator you are using ( / ) this is a floating point
division operator.
What you will want to employ is the often overlooked ( \ ) operator, which
is an integer division operator.
Aside from being much faster then ( / ), you should get your desired
results.
Put this into a function and step through it, monitoring the values of each
variable:

Dim intA, intB As Integer
Dim dblA, dblB As Double
Dim int1, int2, int3, int4 As Integer
Dim dbl1, dbl2, dbl3, dbl4 As Double

intA = 99
intB = 50
dblA = 99.0#
dblB = 50.0#

int1 = intA / intB '=2
int2 = intA \ intB '=1
int3 = dblA / dblB '=2
int4 = dblA \ dblB '=1

dbl1 = intA / intB '=1.98
dbl2 = intA \ intB '=1.0
dbl3 = dblA / dblB '=1.98
dbl4 = dblA \ dblB '=1.0

Gerald
Jul 21 '05 #5
Amazing. I was expecting a simple yes or no answer. Thank you very much,
Teis

"Gerald Hernandez" <Cablewizard@sp *********@Yahoo .com> wrote in message
news:eD******** ******@TK2MSFTN GP10.phx.gbl...

"Teis Draiby" <te************ *@draiby.com> wrote in message
news:u8******** ******@TK2MSFTN GP11.phx.gbl...
In .NET, can I be sure that the result of a division between two integers always is truncated rather that rounded to nearest?

Example:
99 / 50 = 1

regards, Teis

Um, I would have to disagree with those that say yes.
I haven't taken it to the IL or assembly level, but I believe as written

the values will be cast to doubles, divided, then the result rounded to get your Integer. Even if that is not exactly what happens, you will NOT get 1.

The key here is the operator you are using ( / ) this is a floating point
division operator.
What you will want to employ is the often overlooked ( \ ) operator, which
is an integer division operator.
Aside from being much faster then ( / ), you should get your desired
results.
Put this into a function and step through it, monitoring the values of each variable:

Dim intA, intB As Integer
Dim dblA, dblB As Double
Dim int1, int2, int3, int4 As Integer
Dim dbl1, dbl2, dbl3, dbl4 As Double

intA = 99
intB = 50
dblA = 99.0#
dblB = 50.0#

int1 = intA / intB '=2
int2 = intA \ intB '=1
int3 = dblA / dblB '=2
int4 = dblA \ dblB '=1

dbl1 = intA / intB '=1.98
dbl2 = intA \ intB '=1.0
dbl3 = dblA / dblB '=1.98
dbl4 = dblA \ dblB '=1.0

Gerald

Jul 21 '05 #6
Gerald Hernandez <Cablewizard@sp am_remove> wrote:
Um, I would have to disagree with those that say yes.
I haven't taken it to the IL or assembly level, but I believe as written the
values will be cast to doubles, divided, then the result rounded to get your
Integer. Even if that is not exactly what happens, you will NOT get 1.

The key here is the operator you are using ( / ) this is a floating point
division operator.


Well, maybe so if the OP is using VB.NET. Not if they're using C#.
Unfortunately, we have no way of knowing from their post...

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
Jul 21 '05 #7
Jon,

You can use in C# this for what you ask.

int a = (int) 99 / (int) 50;

I hope this helps?

Cor
Jul 21 '05 #8

"Teis Draiby" <te************ *@draiby.com> wrote in message
news:u8******** ******@TK2MSFTN GP11.phx.gbl...
In .NET, can I be sure that the result of a division between two integers
always is truncated rather that rounded to nearest?

Example:
99 / 50 = 1

regards, Teis

Language dependent, not framework dependent.
For example in C++ the behavior is exactly as you describe and can only be
altered by casting one of the operands to a floating point type: double
answer = 99 / 50.0; will result in a real number answer.

--
Peter [MVP Visual Developer]
Jack of all trades, master of none.
Jul 21 '05 #9

"Jon Skeet [C# MVP]" <sk***@pobox.co m> wrote in message
news:MP******** *************** *@msnews.micros oft.com...
Gerald Hernandez <Cablewizard@sp am_remove> wrote:
Um, I would have to disagree with those that say yes.
I haven't taken it to the IL or assembly level, but I believe as written the values will be cast to doubles, divided, then the result rounded to get your Integer. Even if that is not exactly what happens, you will NOT get 1.

The key here is the operator you are using ( / ) this is a floating point division operator.


Well, maybe so if the OP is using VB.NET. Not if they're using C#.
Unfortunately, we have no way of knowing from their post...

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too


Thanks for the additional input. Unfortunately, I forgot to consider C#.
This seems pretty unfriendly, on the part of VB.

Gerald
Jul 21 '05 #10

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