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RegEx replace stuffing spaces

Is there a way to do a Regex replace on a string to stuff some variable
amount of spaces into a location of a string?
I need an expression which would take an unknown length string and move the
last char to position 15.

EX:
123456
transforms to
12345 6

I have a start, but not sure how to do the middle part:
match = "(.*)(.$)"
replace = "$0--spaces go here--$1"
Jul 21 '05 #1
2 3093
Hi Bill,

What about constructing the regular expression dynamically, inserting the
desired number of spaces on the fly? This might be not the best solution if
RegularExpressi ons have some syntax to populate a number character but I
beleive I haven't seen one.

--
Dmitriy Lapshin [C# / .NET MVP]
X-Unity Test Studio
http://x-unity.miik.com.ua/teststudio.aspx
Bring the power of unit testing to VS .NET IDE

"Bill Mittenzwey" <bm*********@ho tmail.com> wrote in message
news:Ou******** ******@TK2MSFTN GP11.phx.gbl...
Is there a way to do a Regex replace on a string to stuff some variable
amount of spaces into a location of a string?
I need an expression which would take an unknown length string and move the last char to position 15.

EX:
123456
transforms to
12345 6

I have a start, but not sure how to do the middle part:
match = "(.*)(.$)"
replace = "$0--spaces go here--$1"


Jul 21 '05 #2
If you use a MatchEvaluator function when you call Replace(), you can do
this kind of thing fairly easily

--
Eric Gunnerson

Visit the C# product team at http://www.csharp.net
Eric's blog is at http://blogs.gotdotnet.com/ericgu/

This posting is provided "AS IS" with no warranties, and confers no rights.
"Bill Mittenzwey" <bm*********@ho tmail.com> wrote in message
news:Ou******** ******@TK2MSFTN GP11.phx.gbl...
Is there a way to do a Regex replace on a string to stuff some variable
amount of spaces into a location of a string?
I need an expression which would take an unknown length string and move the last char to position 15.

EX:
123456
transforms to
12345 6

I have a start, but not sure how to do the middle part:
match = "(.*)(.$)"
replace = "$0--spaces go here--$1"

Jul 21 '05 #3

This thread has been closed and replies have been disabled. Please start a new discussion.

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