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How to calculate time difference between datetime and only time

P: 1
Hi sir, I want to calculate time in a proper format (hours, minute and second).
My first field type is datetime directly fetch from database and second one is fixed it's 08:30:00.
Feb 11 '17 #1
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1 Reply

P: 1
Hi mayurm38.

A date/time/datetime is a fractional number.
The whole number part is the day number where jan 1 1900 is day number 1.
The fractional part is the time. Since a day has 24 hours the value of 1 hour is 1/24 or 0.0416666667. 6 hours is 0.25.

So in order to calculate the time difference only, we have to get rid of the date part.

The next piece of code is one way of doing that.

Expand|Select|Wrap|Line Numbers
  1. Option Compare Database
  2. Option Explicit
  4. Sub timeDifference()
  5.    Dim dt   As Date  'date and time
  6.    Dim tm   As Date  'time only
  7.    Dim dif  As Double
  9.    dt = #2/20/2017 2:30:00 PM#
  10.    tm = #8:30:00 AM#
  12.    dif = dt - Int(dt) - tm 'remove the date(whole number) part from dt
  14.    'next line prints
  15.    ' 0,249999999997575          06:00:00
  17.    Debug.Print dif, Format(dif, "hh:mm:ss")
  18. End Sub
Feb 22 '17 #2

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